Question

A person is standing on a force plate and then jumps off. Below is the measured vertical ground reaction force. From this information, your goal is to calculate how high they jumped You will be using this same approach in the kinetics lab. 2000 1800 1600 1400 1200 1000 800 600 400 200 C 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 Time [sec Below is a general guide for solving this problem - Use the graph above to calculate the total impulse applied by the person (remember to consider both positive and negative impulses - Use the impulse momentum equation to calculate the velocity at lift off - Use that velocity to estimate jump height (either using standard kinematic equations physics) or conservation of energy principles from Force [N]

Answer 1

F +660 600 K I J 04 05 06 07 08 O 2 03 for ce CN)

Owhan fesson was amton ore late hon R g600N (See tha graph) -6o0 9.& 6122g Peseson Stas un at 0-2s amd laave e Flati at Lmbulbe ey toace area Under the ash atingm 02s to dss Cea f trabeziun Bcfa+ ar CDOP +arl trap DENO'+arl thap EFMN) +a Ctap FG LM)tarltp GHIL) x (BQ+c)xa+ XCP+D0)xP0 X DEN) EN+ FNXNN - XNOナ + +4x(FM+GL)メ ML+X(GL+HI)x LT X(60044)X0-1+(40t6)r0 D +x (600+160) yC)x(600+20gx0 X x(205D+ 16Dxol+(600 t6o)x0) 50+50+10ナ100t00+1l0 $680 N-8

unitally feeson was at est en lata we Rmo tRat Tmfulde change im mementunm mt1) 61-22 (-0) 680 11.118 61-22 Eneg BY Consewatlon KE at he dinme weu peeson ut Flate laave the PE at max tght 1-112 K9.8 Capprox-) 11