Question

A particle is confined between rigid walls separated by a distanceL = 0.189 nm. The particle is in the second exited state (n = 3).Evaluate the probability to find the particle in an interval ofwidth 1.00 pm located at: (a) x = 0.188 nm; (b) x = 0.031 nm; (c) x= 0.079 nm. (Hint: No integrations are required for this problem;use Equation 5.4 directly.) What would be the corresponding resultsfor a classical particle?

Equation 5.4 is
A particle is confined between rigid walls separated by a distanceL = 0.189 nm. The particle is in the second exited state (n = 3).Evaluate the probability to find the particle in an interval ofwidth 1.00 pm located at: (a) x = 0.188 nm; (b) x = 0.031 nm; (c) x= 0.079 nm. (Hint: No integrations are required for this problem;use Equation 5.4 directly.) What would be the corresponding resultsfor a classical particle? Equation 5.4 is P( x )dx = |psi(x)|^2 dx Thank you.


Thank you.

Answer 1

   

Answer 2

theres a error in the solution:

CORRECTION: dx = 1.00 pm = 1.00 x 10^-12 m

NOT: 1.00 x 10^-9 m

Answer 3

Where does the interval width of 1.00 pm come in? Do I multiplythis interval width with the wave function squared? It looks likecalculating these values will give probabilities greater than 1.Can you please explain more. Thank you for your help.