A person consumes about 2400Cala day.1 Cal = 4186 J, and 1 kWh = 860 Cal. What is the energy in Joules?
2400 Cal = 2400*4186 = 10046400 joules = 2.79 kWh
1 kWh = 860 Cal = 860*4186 = 3599960 joules.
A person consumes about 2400Cala day.1 Cal = 4186 J, and 1 kWh = 860 Cal....
A person consumes about 2200Cala day.1 Cal = 4186 J, and 1 kWh = 860 Cal. What is this energy in joules?. What is this energy in kilowatt-hours?
A person consumes about 2900Cal a day. 1 Cal = 4186 J , and 1 kWh = 860 Cal . A) What is the energy in joules? Q=? J B) What is this energy in kilowatt-hours? Q=? kWh C) If a power company charges about 14
A person consumes about 2600 Cal a day. 1 Cal = 4186 J, and 1 kWh = 860 Cal. A)What is this energy in joules? B)What is this energy in kilowatt-hours? C)If a power company charges about 13 ¢ per kilowatt-hour, how much would this energy cost per day if the person bought it from the power company?
14.04 A person consumes about 2600 Cal a day. 1 Cal = 4186 J, and 1 kWh = 860 Cal. A) What is this energy in joules? B)What is this energy in kilowatt-hours? C)If a power company charges about 13 ¢ per kilowatt-hour, how much would this energy cost per day if the person bought it from the power company?
A person consumes about 2300 Cal a day. 1 Cal = 4186 J, and 1 kWh = 860 Cal. Part A What is this energy in joules? Express your answer using two significant figures. Q Q = nothing J SubmitRequest Answer Part B What is this energy in kilowatt-hours? Express your answer using two significant figures. Q Q = nothing kWh SubmitRequest Answer Part C If a power company charges about 10 ¢ per kilowatt-hour, how much would this energy...
Problem 14.04 A person consumes about 2900 Cal a day. 1 Cal = 4186 J, and 1 kWh = 860 Cal. Part A What is this energy in joules? Express your answer using two significant figures. Q = m J SubmitMy AnswersGive Up Part B What is this energy in kilowatt-hours? Express your answer using two significant figures. Q = m kWh SubmitMy AnswersGive Up Part C If a power company charges about 14 ¢ per kilowatt-hour, how much would...
3. An average active person consumes about 2500 Cal (1 Cal =1000 cal) per day. (a) What is this in joules? (b) What is this in kilowatt-hours? (c) If your power company charges about 30 ¢ per kilowatt-hour, how much would your energy cost per day if you bought it from the power company? Just for fun… Do you think you could you feed yourself (adequately) on this much money per day? show work!!
1. Let’s say that an average person consumes about 2000 calories per day over their entire lifetime. A calorie (Cal) is a unit of energy and one Cal equals 4186 ? (Joules). For someone who lives to a ripe age of 100 years, how much energy, in J will they require? What is their average power output in ?/? = ????? (abbreviated ?)? b) Given the total energy a person requires that you calculated above, use Einstein’s equation to determine...
In one day, the average food intake for a person in the United States is about 2500 kilocalories (1 cal = 4.2 J). Assuming half of this energy goes into work (the other half goes into heat radiated by the body), what is the average power output (in watts) of a person for 24 hours?
A common unit of energy used in food chemistry is the food calorie (1 Cal = 4186 J). What speed must a 42 kg person walk to have a kinetic energy equal to a donut (300 Cal)?