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An article proposes the Weibull distribution with a 1.817 and B 0.883 as a model for 1-hour significant wave height (m) at a

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Answer #1

a)

P(X<0.5) =1-exp(-(0.5/0.883)^1.817)=0.2994

b)

P(X exceeds mean +standard deviation) =0.1622

c)

median =0.883*(-ln(0.5))1/1.817 =0.722

d)

n(p) =0.883*(-ln(1-p))1/1.817

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