What is the pOH of 0.022M NaC3H5O2?
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NaC3H5O2 (aq) -------------> Na^+ (aq) + C3H5O2^- (aq)
0.022M 0.022M
C3H5O2^- (aq) + H2O(l) ------------------> C3H5O2H(aq) + OH^- (aq)
I 0.022 0 0
C -x +x +x
E 0.022-x +x +x
Kb = Kw/Ka
= 1*10^-14/(1.34*10^-5) = 7.46*10^-10
Kb = [C3H5O2H][OH^-]/[C3H5O2^-]
7.46*10^-10 = x*x/(0.022-x)
7.46*10^-10*(0.022-x) = x^2
x = 4.05*10^-6
[OH^-] =x = 4.05*10^-6M
POH = -log[OH^-]
= -log(4.05*10^-6)
= 5.3925 >>>>>answer
What is the pOH of 0.022M NaC3H5O2? *Please show every single step or I'll thumbs down....
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