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Hi, please help me with this exercise please explain
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Question Completion Status: QUESTION 1 10 points A hydrocarbon gas is burned with air. The dry-basis...
Question Completion Status: QUESTION 1 10 points A hydrocarbon gas is burned with air. The dry-basis (without H20) product gas composition is 1.5 mole% CO, 6 mole% CO2, 8.2 mole% O2, and 84.3 mole% N2. ne(mol C) (mol no (malain (100 mol dry gas 0.21 mol Oymol 0.015 mol COmol dry gas 0.79 mol Ny/mol 0.060 mol CO2 mol dry gas 0.082 mol Oz moi dry g 0.843 mol Nymol dry gas "wmol H20) 1. Using the method of atomic...
Methane gas is burned with 30 percent excess air. This fuel enters a steady-flow combustor at 0.9 atm and 25'C...
Methane gas is burned with 30 percent excess air. This fuel enters a steady-flow combustor at 0.9 atm and 25'C and is mixed with the air. The products of combustion leave this reactor at 0.9 atm and 1600 K. Determine the equilibrium composition of the products of combustion and the amount of heat released by this combustion in kJ/kmol methane. Use data from the tables. CH4 Combustion 25℃ CO, HO 1600 K 30%acess 25 C The amount of carbon dioxide...
100 moles/h of methane is burned with 100% excess air. The percent conversion of methane is...
100 moles/h of methane is burned with 100% excess air. The percent conversion of methane is 70%. Of the methane burned, 32% is reacted in partial combustion and the balance reacts in complete combustion. The reaction schemes are shown below: (1) CH4 + 2O2→ CO2 + 2H2O (2) CH4 + 3/2O2→ CO + 2H2O a. Draw a flow chart for this process b. Calculate the inlet air flow rate in moles/h c. Calculate the molar flow rate in moles/h and...
4. a. (18 points) Ethane (CH) is burned with dry air, giving the products having a...
4. a. (18 points) Ethane (CH) is burned with dry air, giving the products having a molar analysis on a dry basis: CO2, 7.8%; CO, 0.2%, 02, 7%; N2, 85% (actual combustion). Determine: (3 points each) (a) the stoichiometric air-fuel ratio. (b) the actual air fuel ratio on molar and mass bases based on the given products of combustion. (c) the gravimetric wet analysis (mass fractions) of the products of the actual combustion. (d) the gas constant of the products...
Hi, please help me with this problem, please explain me step by step and write with very good cal...
Hi, please help me with this problem, please explain me step by step and write with very good calligraphy. Solve the next problems: * Water is heated in a horizontal tube. Water enters at a rate of 6 lbm / s and 60 ° F and is heated to 300 ° F. The water flows through an aluminum tube of 3 in diameter. The pipe is heated by an electric resistance ratio of 405Btu / h per foot of pipe...
Problem 4.84 Combustion Mixture A gas contains 75.0 wt% methane, 10.00 wt% ethane, 5.00 wt% ethylene,...
Problem 4.84 Combustion Mixture A gas contains 75.0 wt% methane, 10.00 wt% ethane, 5.00 wt% ethylene, and the balance water. Composition Calculate the molar composition of this gas on both a wet and a dry basis and the ratio (mol H20/mol dry gas). Component Mole % (Wet basis) Mole % (Dry basis) Methane 81.5 90.22 Ethane 5.74 6.35 Ethylene 3.09 3.42 Water 9.66 mol H20/mol dry gas: Click if you would like to Show Work for this question: Open Show...
Problem 4.84 Combustion Mixture A gas contains 75.0 wt% methane, 10.00 wt% ethane, 5.00 wt% ethylene,...
Problem 4.84 Combustion Mixture A gas contains 75.0 wt% methane, 10.00 wt% ethane, 5.00 wt% ethylene, and the balance water. Composition Calculate the molar composition of this gas on both a wet and a dry basis and the ratio (mol H20/mol dry gas). Component Mole % (Wet basis) Mole % (Dry basis) Methane 81.5 90.22 Ethane 5.74 6.35 Ethylene 3.09 3.42 Water 9.66 mol H20/mol dry gas: Click if you would like to Show Work for this question: Open Show...
Hi, please help me with this exercise, please explain me step by step and please write...
Hi, please help me with this exercise, please explain me step by
step and please write with very very good calligraphy. Thank you
very much.
* From an urn containing 4 white balls and 3 black balls 3 balls
are removed with replacement. Following this, a coin is thrown as
many times as black balls have been removed and the amount of heads
obtained is evaluated. We define X as the random variable that
represents the quantity of black balls...
A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of...
A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of the combustion gas is 5.34% CO2, 13.23% O2 and 81.43% N2. The molal humidity of the product is 0.179 mol water vapor/mol of dry gas. Calculate percent composition by weight of the liquid fuel.
A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of...
A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of the combustion gas is 5.34% CO2, 13.23% O2 and 81.43% N2. The molal humidity of the product is 0.179 mol water vapor/mol of dry gas. Calculate percent composition by weight of the liquid fuel.
Question Completion Status: QUESTION 1 10 points A hydrocarbon gas is burned with air. The dry-basis (without H20) product gas composition is 1.5 mole% CO, 6 mole% CO2, 8.2 mole% O2, and 84.3 mole% N2. ne(mol C) (mol no (malain (100 mol dry gas 0.21 mol Oymol 0.015 mol COmol dry gas 0.79 mol Ny/mol 0.060 mol CO2 mol dry gas 0.082 mol Oz moi dry g 0.843 mol Nymol dry gas "wmol H20) 1. Using the method of atomic...
Methane gas is burned with 30 percent excess air. This fuel enters a steady-flow combustor at 0.9 atm and 25'C and is mixed with the air. The products of combustion leave this reactor at 0.9 atm and 1600 K. Determine the equilibrium composition of the products of combustion and the amount of heat released by this combustion in kJ/kmol methane. Use data from the tables. CH4 Combustion 25℃ CO, HO 1600 K 30%acess 25 C The amount of carbon dioxide...
4. a. (18 points) Ethane (CH) is burned with dry air, giving the products having a molar analysis on a dry basis: CO2, 7.8%; CO, 0.2%, 02, 7%; N2, 85% (actual combustion). Determine: (3 points each) (a) the stoichiometric air-fuel ratio. (b) the actual air fuel ratio on molar and mass bases based on the given products of combustion. (c) the gravimetric wet analysis (mass fractions) of the products of the actual combustion. (d) the gas constant of the products...
Problem 4.84 Combustion Mixture A gas contains 75.0 wt% methane, 10.00 wt% ethane, 5.00 wt% ethylene, and the balance water. Composition Calculate the molar composition of this gas on both a wet and a dry basis and the ratio (mol H20/mol dry gas). Component Mole % (Wet basis) Mole % (Dry basis) Methane 81.5 90.22 Ethane 5.74 6.35 Ethylene 3.09 3.42 Water 9.66 mol H20/mol dry gas: Click if you would like to Show Work for this question: Open Show...
Problem 4.84 Combustion Mixture A gas contains 75.0 wt% methane, 10.00 wt% ethane, 5.00 wt% ethylene, and the balance water. Composition Calculate the molar composition of this gas on both a wet and a dry basis and the ratio (mol H20/mol dry gas). Component Mole % (Wet basis) Mole % (Dry basis) Methane 81.5 90.22 Ethane 5.74 6.35 Ethylene 3.09 3.42 Water 9.66 mol H20/mol dry gas: Click if you would like to Show Work for this question: Open Show...
Hi, please help me with this exercise, please explain me step by
step and please write with very very good calligraphy. Thank you
very much.
* From an urn containing 4 white balls and 3 black balls 3 balls
are removed with replacement. Following this, a coin is thrown as
many times as black balls have been removed and the amount of heads
obtained is evaluated. We define X as the random variable that
represents the quantity of black balls...
A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of the combustion gas is 5.34% CO2, 13.23% O2 and 81.43% N2. The molal humidity of the product is 0.179 mol water vapor/mol of dry gas. Calculate percent composition by weight of the liquid fuel.
A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of the combustion gas is 5.34% CO2, 13.23% O2 and 81.43% N2. The molal humidity of the product is 0.179 mol water vapor/mol of dry gas. Calculate percent composition by weight of the liquid fuel.
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