100 moles/h of methane is burned with 100% excess air. The percent conversion of methane is 70%. Of the methane burned, 32% is reacted in partial combustion and the balance reacts in complete combustion. The reaction schemes are shown below:
(1) CH4 + 2O2→ CO2 + 2H2O
(2) CH4 + 3/2O2→ CO + 2H2O
a. Draw a flow chart for this process
b. Calculate the inlet air flow rate in moles/h
c. Calculate the molar flow rate in moles/h and composition of the stack gas on a wet basis
100 moles/h of methane is burned with 100% excess air. The percent conversion of methane is...
Methane gas is burned with 30 percent excess air. This fuel enters a steady-flow combustor at 0.9 atm and 25'C and is mixed with the air. The products of combustion leave this reactor at 0.9 atm and 1600 K. Determine the equilibrium composition of the products of combustion and the amount of heat released by this combustion in kJ/kmol methane. Use data from the tables. CH4 Combustion 25℃ CO, HO 1600 K 30%acess 25 C The amount of carbon dioxide...
Calculate the work (in kJ) when 2.60 moles of methane react with excess oxygen at 366 K: CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)
Part E Calculate the approximate enthalpy change , ?H?, for the combustion of methane: CH4+2O2?2H2O+CO2 Use the values you calculated in Parts A to D, keeping in mind the stoichiometric coefficients. Please explain.
Please explain Question 4 746 Ethane (C2H6) is burned with 50% excess air. The percentage conversion of the ethane is 90% Of the ethane burned, 25% reacts to form CO and the balance to form CO2. Calculate the composition of the fuel gas and the ratio of water to dry fuel gas. (40) [40 marks]
1. Calculate the work (in kJ) when 1.80 moles of methane react with excess oxygen at 425 K: CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) 2. Using the technique of the previous problem ΔE was found to be -2,000.00 kJ/mol of an unknown liquid hydrocarbon at 298 K. In another experiment it was determined that for each mole of hydrocarbon, 5 moles of oxygen gas are consumed and 9 moles of CO2 gas and 4 moles of H2O liquid are...
Problem 2 CH 25 C Products 150 C Air 100 25 C Cooling water Methane (CH4) is oxidized with air to produce formaldehyde (HCHO) in a continuous reactor via the following reaction: A competing reaction is the combustion of methane to form CO2: In this specific problem, CH4 and O2 enter the reactor at a mole ratio of 1:1. In the reactor, 40% of CH4 is consumed. Of this 40%, 75% reacted via reaction (1) and the other 25% reacted...
Problem 4.84 Combustion Mixture A gas contains 75.0 wt% methane, 10.00 wt% ethane, 5.00 wt% ethylene, and the balance water. Composition Calculate the molar composition of this gas on both a wet and a dry basis and the ratio (mol H20/mol dry gas). Component Mole % (Wet basis) Mole % (Dry basis) Methane 81.5 90.22 Ethane 5.74 6.35 Ethylene 3.09 3.42 Water 9.66 mol H20/mol dry gas: Click if you would like to Show Work for this question: Open Show...
Problem 4.84 Combustion Mixture A gas contains 75.0 wt% methane, 10.00 wt% ethane, 5.00 wt% ethylene, and the balance water. Composition Calculate the molar composition of this gas on both a wet and a dry basis and the ratio (mol H20/mol dry gas). Component Mole % (Wet basis) Mole % (Dry basis) Methane 81.5 90.22 Ethane 5.74 6.35 Ethylene 3.09 3.42 Water 9.66 mol H20/mol dry gas: Click if you would like to Show Work for this question: Open Show...
A liquid fuel containing C, H and O, was burned completely using excess air. The Orsat analysis of the combustion gas shows 4.48% CO2, 11.21% O2 and 84.31% N2, And the molal humidity of the product gas is 0.179 mol water vapor per mol of dry gas. Calculate % composition by weight of the liquid fuel.
A liquid fuel containing C, H and O, was burned completely using excess air. The Orsat analysis of the combustion gas shows 4.48% CO2, 11.21% O2 and 84.31% N2, And the molal humidity of the product gas is 0.179 mol water vapor per mol of dry gas. Calculate % composition by weight of the liquid fuel.