A.B=ABcos(theta)=34*61*cos(70-20)=1333.14
B.(A+C)=B.A+B.C
B.C=CBcos(theta)=21*61*cos(70+20)=0
B.(A+C)=A.B=ABcos(theta)=34*61*cos(70-20)=1333.14
answers is 110 degree above and 70 degree below
In the figure below are three vectors. Vector A has a length of 340, B?s length...
help In the figure below are three vectors. Vector A has a length of 35.0, B's length is 61.0, and C is 23.0. Find the following magnitudes and directions: At what angles above and below the horizontal line could vector A be at so that A times B = 0?
In the figure below are three vectors Vector A has a length of 360. B?s length is 66.0, and C is 25.0. Find the following magnitudes and directions At what angles above and below the horizontal line could vector A be at so that A x B = 0?
In the figure below are three vectors. Vector A has a length of 33.0, B's length is 64.0, and C is 21.0. Find the following: Number A А. В %— 700 Number 20° 7+C) B . 70° C At what angles above and below the horizontal line could vector A be at so that A B 0? 20° above, or 160° below 90° above, or 90° below 110° above, or 70° below 90° above, or 70° below
In the figure below are three vectors. Vector A has a length of 36.0, B?s length is 65.0, and C is 24.0.Find the following magnitudes and directions:At what angles above and below the horizontal line could vector A be at so that A x B = 0?90 degree above, or 70 degree below20 degree above, or 160 degree below110 degree above, or 70 degree below0 degree above, or 180 degree below
Physics: In the figure below are three vectors. Vector A has a length of 39.0, B's length is 63.0, and C is 21.0. Find the following magnitudes and directions: At what angles above and below the horizontal line could vector A be at so that A Times B = 0? 90 degree above, or 70 degree below 110 degree above, or 70 degree below 0 degree above, or 180 degree below 20 degree above, or 160 degree below
In the figure below are three vectors. Vector A has a length of 38.0, B\'s length is 64.0, and C is 23.0. Find the following: 1. A(dot)B = ? 2. B(dot)(A+C) = ? 3. At what angles above and below the horizontal line could vector A be at so that A·B = 0? a. 90 degrees above, 90 degrees below b. 90 degrees above, 70 degrees below c. 110 degrees above, 70 degrees below d. 20 degrees above, 160 degrees...
Each of the displacement vectors [vector A] and [vector B] shown in the figure below has a magnitude of 3.00 m. Find the following values graphically. Report all angles counterclockwise from the positive x axis. (a) [vector A] + [vector B]=? maginitude=? θ °=? (b) [vector A] - [vector B]=? magnitude =? θ °=? (c) [vector B] - [vector A]=? magnitude=? θ °=? (d) [vector A] - 2 [vector B]=? magnitude=? θ °=?
Help please 4. Consider the three displacement vectors shown in the figure: Vector A has a magnitude of 7.70 km and a direction that makes an angle θ 26.0 to the left of the positive y-axis, vector B has a magnitude of 6.00 km and a direction that makes an angle of α-200° above the positive x-axis, and vector C has a magnitude of 4.20 km and a direction that makes an angle B 61.0° below the negative x-axis. Determine...
4 Consider the three displacement vectors shown in the figure: Vector A has a magnitude of 780 km and a direction that makes an angle θ 340 to the left of the positive y-axis, vector has a magnitude of 5.00 km and a direction that makes an angle of α-260 above the positive x-axis, and vector C has a magnitude of 3,90 km and a direction that makes an angle B-57.0° below the negative x-axis. Determine the magnitude of the...
4. Consider the three displacement vectors shown in the figure: Vector Á has a magnitude of 8.30 km e-230 to the left of the positive y-axis, vector B has a magnitude of 6.00 km and a direction that makes an angle of α 340° above the positive x-axis, and vector d has a magnitude of 4.20 km and a direction that makes an angle B-630° below the negative x-axis. Determine the magnitude of the vector iD A-B and a direction...