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Image for In the figure below are three vectors. Vector A has a length of 340, B?s length is 61.0. and C is 21.0. Find t

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Answer #1

A.B=ABcos(theta)=34*61*cos(70-20)=1333.14

B.(A+C)=B.A+B.C

B.C=CBcos(theta)=21*61*cos(70+20)=0

B.(A+C)=A.B=ABcos(theta)=34*61*cos(70-20)=1333.14

answers is 110 degree above and 70 degree below

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