A x B = |A||B| sin theta = 36*65*sin(70 degrees)=2199
A into b gives into the page
C x B = |C||B| sin theta = 24*65*sin(90 degrees)= 1560
C into B gives out of the page
3) so we want angle between A and B to be parallel to anti parallelt
so 20 above or 160 below
In the figure below are three vectors. Vector A has a length of 36.0, B?s length...
Physics:
In the figure below are three vectors. Vector A has a length of 39.0, B's length is 63.0, and C is 21.0. Find the following magnitudes and directions: At what angles above and below the horizontal line could vector A be at so that A Times B = 0? 90 degree above, or 70 degree below 110 degree above, or 70 degree below 0 degree above, or 180 degree below 20 degree above, or 160 degree below
In the figure below are three vectors Vector A has a length of 360. B?s length is 66.0, and C is 25.0. Find the following magnitudes and directions At what angles above and below the horizontal line could vector A be at so that A x B = 0?
In the figure below are three vectors. Vector A has a length of
38.0, B\'s length is 64.0, and C is 23.0. Find the following:
1. A(dot)B = ?
2. B(dot)(A+C) = ?
3. At what angles above and below the horizontal line could
vector A be at so that A·B = 0?
a. 90 degrees above, 90 degrees below
b. 90 degrees above, 70 degrees below
c. 110 degrees above, 70 degrees below
d. 20 degrees above, 160 degrees...
In the figure below are three vectors. Vector A has a length of 33.0, B's length is 64.0, and C is 21.0. Find the following: Number A А. В %— 700 Number 20° 7+C) B . 70° C At what angles above and below the horizontal line could vector A be at so that A B 0? 20° above, or 160° below 90° above, or 90° below 110° above, or 70° below 90° above, or 70° below
In the figure below are three vectors. Vector A has a length of 340, B?s length is 61.0. and C is 21.0. Find the following: At what angles above and below the horizontal line could vector A be at so that k B = 0?
help
In the figure below are three vectors. Vector A has a length of 35.0, B's length is 61.0, and C is 23.0. Find the following magnitudes and directions: At what angles above and below the horizontal line could vector A be at so that A times B = 0?
Vector A has a magnitude of 146 units and points 36.0° north of west. Vector B points 63.0° east of north. Vector points 16.0° west of south. These three vectors add to give a resultant vector that is zero. Using components, find the magnitudes of the following vectors e) vector B x units (b) vector C x units Enter a number
Each of the displacement vectors [vector A] and [vector B] shown in the figure below has a magnitude of 3.00 m. Find the following values graphically. Report all angles counterclockwise from the positive x axis. (a) [vector A] + [vector B]=? maginitude=? θ °=? (b) [vector A] - [vector B]=? magnitude =? θ °=? (c) [vector B] - [vector A]=? magnitude=? θ °=? (d) [vector A] - 2 [vector B]=? magnitude=? θ °=?
following
The two vectors α and b in the figure below have equal magnitudes of 13.1 m and their angles are a = 30° and θ2-1039 0 (a) Find the x and y components of their vector sum r. (Express your answer in vector form.) (b) Find the magnitude of (c) Find the angle r makes with the positive x axis
Given are three vectors. Vector
Aof magnitude 5.30 units is in a direction θ =
36.0° above the positive x-axis. Vector
Bof magnitude 5.00 units is directed in the
direction of the positive y-axis. Vector
C of magnitude 5.80 units is in a direction ϕ =
37.0° clockwise from the negative y-axis.
Find the magnitude and direction of 2A −
B + 3C
magnitude
units
direction
° counterclockwise from the +x-axis
+y 10 16 0 +x 10 e