Question

Must be done in Java.

PROBLEM 1 INFORMATION AND THE CODE PROVIDED WITH IT AS WELL.

Provide the rest of the code with full comments and explanation and with proper indentation.

Use simple methods for better understanding.

Must compile.

At the end show the exact Output that's shown in the Problem 2.

CODE PROVIDED FOR PROBLEM 1:

import java.util.Scanner;

public class Problem1
{
   public static void main( String [] args )
   {
       //N denoting the size of the board
       int n;
       //B denoting the number of black pieces to be place on the board
       int b;
       //row and column position of a piece
       int r,c;
       //W denoting the number of white pieces to be place on the board
       int w;
      
       int i,j;
       Scanner in = new Scanner(System.in);
      
       n = in.nextInt();
      
       String[][] board = new String[n][n];
       //initialize the board with periods
       for(i = 0;i<n;i++)
       {
           for(j = 0;j<n;j++)
           {
               board[i][j] = ".";
           }
       }
      
       //take b and its r and c positions in one line of input
       //and remove any whitespaces at end and start, split at space to separate values
       in.nextLine();
       String[] inp = in.nextLine().trim().split(" ");
      
       //B will the first value in the splitted input stored in the string array
       b = Integer.parseInt(inp[0]);
       for(i = 1;i<2*b;i+=2)
       {
           r = Integer.parseInt(inp[i]);
           c = Integer.parseInt(inp[i+1]);
           //check for row and column exceed conditions .
           //positions must be in range of n
           if(r >=0 && r<n)
           {
               if(c >=0 && c< n)
               {
                   //set black posiiton in board
                   board[n - r - 1][c] = "*";
                  
               }
           }
       }
      
       //take W and its r and c positions in one line of input
       //and remove any whitespaces at end and start, split at space to separate values
      
       inp = in.nextLine().trim().split(" ");
      
       //W will the first value in the splitted input stored in the string array
       w = Integer.parseInt(inp[0]);
       for(i = 1; i<2*w ; i+=2)
       {
           r = Integer.parseInt(inp[i]);
           c = Integer.parseInt(inp[i+1]);
           //check for row and column exceed conditions .
           //positions must be in range of n
           if(r >=0 && r<n)
           {
               if(c >=0 && c< n)
               {
                   //set white piece position in board
                   board[n - r - 1][c] = "0";
                  
               }
           }
       }
       //finally print out the board
       for(i = 0;i<n;i++)
       {
           for(j = 0;j<n;j++)
           {
               System.out.print(board[i][j]+" ");
           }
           System.out.println();
       }
   }
}

___________________________________________________________________________________

30 points! Now you are well PROBLEM 2: CHECK IT OUT! on your way! In checkers, players take turns moving their pieces. Starting with your solution to Problem 1, extend it so that given a board size N, the positions of the black and white checkers, a sequence of valid moves, it prints out the resulting checker board. INPUT Sample Input One move The same input as in Problem 1, followed by Integer M denoting the number of moves, followed by 4M integers R, C, R2 C2 denoting the row and column of the start and end position 30 2 1 1 1 3 2 2 0 3 3 3 1 1 2 2 2 1 1 2 2 3 1 of a move l.e., the piece at R, c, is moved to R2 C2 Sample Output PROCESSING: *.0 You may assume that every move is valid The final board configuration is what is to be printed .0. OUTPUT Output is the same format as Problem 1 50 points! Complete this and you'll have passed! PROBLEM 1: A CHECKERED PAST Checkers is played on an N XN checker board, with one side playing the black pieces and the other side playing the white pieces. Given a board size N and the positions of the black and white checkers, create a program to print out the resulting checker board. INPUT Row, Column Integer N denoting the size of the board Integer B denoting the number of black pieces to be placed on the board, followed by B pairs of integers R C denoting the row and column of B black pieces Sample Input N Integer W denoting the number of white pieces to be placed on the board, followed by W pairs of integers R C denoting the row and column of W white pieces 4 3 2 1 1 1 3 2 2 3 3 W PROCESSING: The bottom left corner of the board is (0, o) and the top right corner is (N-1,N-1) (4,0) Sample Output 2 0 |(4,4) ...0 OUTPUT 0. Output an Nx N board, where an empty square is denoted by a period ., a black piece is denoted by an asterisk *', and a white piece is denoted by the letter o' 0 2 (0,0 |(0,4)

Answer 1

Solution.java package vbv import java.util.Scanner; public class Solution public static void main(String [] args) { 1TODO Auto-generated method stub int n,R1,C1, R2, C2, count=0, count1-0; Scanner sc new Scanner (System.in); /input the size of the board System.out.print("Enter the size of board:"); n sc.nextInt (); //filling the board with empty values char board[][ for (int i-0;i<n; i++) { for(int j-0;j<n;j++) char[n][n] = new board[i]j System.out.println ("Initially the board is"); //displaying the board displayBoard(board, n) int b,w,r,c; //input black pieces System.out.print (" \nEnter number of black pieces:"); b sc.nextInt (); System.out.println ( "Enter "+b+" pairs of R C denoting //placing the black pieces into the board for (int i-1;i<-b; i++) { r sc.nextInt ); c sc.nextInt ); board[r][c] row and column"); //input the white pieces System.out.print ("\nEnter number of white pieces:"); w sc.nextInt ( ); System.out.println ("\n Enter "tw+" pairs of R C denoting //placing the white pieces into the board row and column")

Code:

package vbv;
import java.util.Scanner;
public class Solution {
   public static void main(String[] args)
   {
   // TODO Auto-generated method stub
   int n,R1,C1,R2,C2,count=0,count1=0;
   Scanner sc = new Scanner(System.in);
   //input the size of the board
   System.out.print("Enter the size of board:");
   n = sc.nextInt();
   //filling the board with empty values
   char board[][] = new char[n][n];
   for(int i=0;i<n;i++)
   {
   for(int j=0;j<n;j++)
   {
   board[i][j] = '.' ;
   }
   }
  
   System.out.println("Initially the board is");
   //displaying the board
   displayBoard(board,n);
   int b,w,r,c;
   //input black pieces
   System.out.print("\nEnter number of black pieces:");
   b =sc.nextInt();
   System.out.println("Enter "+b+" pairs of R C denoting row and column");
   //placing the black pieces into the board
   for(int i=1;i<=b;i++)
   {
   r = sc.nextInt();
   c = sc.nextInt();
   board[r][c] = '*';
   }
   //input the white pieces
   System.out.print("\nEnter number of white pieces:");
   w =sc.nextInt();
   System.out.println("\nEnter "+w+" pairs of R C denoting row and column");
   //placing the white pieces into the board
   for(int i=1;i<=w;i++)
   {
   r = sc.nextInt();
   c = sc.nextInt();
   board[r][c] = 'O';
   }
   System.out.println("After putting the black and white pieces the board is");
   //displaying the board
   displayBoard(board,n);
   //For Problem 2 taking initial position and final position of pieces from user as input
   System.out.println("\n Enter R1 and C1(Initisl position) and R2 andC2 (final)");
   R1=sc.nextInt();
   C1=sc.nextInt();
   R2=sc.nextInt();
   C2=sc.nextInt();
   for(int i=0;i<n;i++)
   {
   for(int j=0;j<n;j++)
   { //This step will check if the initial position if found and if it is white piece
   if(board[i][j]==board[R1][C1])
   {
   if(board[i][j]=='O')
   {
   count++; /* If the piece is white count=1 else 0. This will help us to place the piece correctly in the next step*/
   board[i][j]='.';
   }
   }
   if(board[i][j]==board[R1][C1])
   {
   if(board[i][j]=='*')
   {
   count1++;
   board[i][j]='.';
   }
   }
   }
   }
   displayBoard(board,n);
   for(int i=0;i<n;i++)
   {
   for(int j=0;j<n;j++)
   {
   if(board[i][j]==board[R2][C2])
   {
   if(count==1)
   board[i][j]='O';// count=1 means white piece
   }
   if(board[i][j]==board[R2][C2])
   {
   if(count1==1)
   board[i][j]='*'; // count=0 means a black piece
   }
   }
   }
   System.out.println("After putting the black and white pieces the board is");
   //displaying the board
   displayBoard(board,n);
   }
   //method to display the board
   public static void displayBoard(char[][] board, int size)
   {
   for(int i=0;i<size;i++)
   {
   System.out.println();
   for(int j=0;j<size;j++)
   {
   System.out.print(board[i][j]+"\t");
   }
   }
   }
   }

Output:

@ Javadoc Declaration Console Problems Solution [Java Application] C:\Program Files (x86)Javaljre1.8.0 191\bin\javaw.exe (Jun 17, 2019, 3:51:10 PM) Enter the size of board:4 Initially the board is Enter number of black pieces:4 pairs of R C denoting row and column Enter 4 2 1 Enter number of white pieces:3 Enter 3 pairs of R C denoting row and column 2 After putting the black and white pieces the board is C Enter R1 and C1 ( Initisl position) and R2 andC2 (final)