Question

Checkers is played on an N XN checker board, with one side playing the black pieces and the ofther side playing the white pieces. Glven a board size N and the positions of the black and white checkers, create a program to print out the resulting checker board. INPUT Row, Column Integer N denoting the size of the board Integer B denoting the number of black pieces to be placed on the board, followed by B pairs of integers R C denoting the row and column of B black pieces Sample Input N Integer W denoting the number of white pieces to be placed on the board, followed by W pairs of integers R C denoting the row and column of W white pieces 4 B 3 2 11 1 3 2 2033 w PROCESSING: The bottom left corner of the board is (0, 0) and the top right corner is (N-1,N-1) Sample Output 20 (4,0) 0 (4,4) OUTPUT 0 Output an NxN board, where an empty square is denoted by a period '., a black piece is denoted by an asterisk , and a white piece is denoted by the letter '0' 02 (0,0 (0,4)

please use JAVA to solve it.

Answer 1

The following code in java can help in doing this question.

Some points of information:

1. Scanner is used to take input from the user.

2. For using the regular convention with rows and columns (n-r-1) is done to flip the row number.

The code is as follows:

import java.util.Scanner;

public class Program{

public static void main(String []args){
Scanner scan = new Scanner(System.in);
int n = scan.nextInt();
char[][] arr = new char[n][n];
for(int i=0; i<n; i++){
for(int j=0; j<n; j++){
arr[i][j] = '.';
}
}
  
int b = scan.nextInt();
for(int i=0; i<b; i++){
int r = scan.nextInt();
int c = scan.nextInt();
arr[n - r - 1][c] = '*';
}
int w = scan.nextInt();
for(int i=0; i<w; i++){
int r = scan.nextInt();
int c = scan.nextInt();
arr[n - r - 1][c] = 'O';
}

for(int i=0; i<n; i++){
for(int j=0; j<n; j++){
System.out.print(arr[i][j]);
}
System.out.println(' ');
}
}
}

Execution:

Input:

4 30 2 1113 22033

Output:

Output: . .0 0...

Hope this helps :)