Question

In Python 3 only please. A simple function that will be used on a file.

commonpair(str) – Takes a single string argument, representing the first word. This function should return the word that most frequently followed the given argument word (or one of, in case of ties). If the argument word does not appear in the text at all, or is never followed by another word (i.e., is the last word in the file), this function should return None.

I did the code but it does not do what's mentioned.

#Commonpair method
def commonpair(str):

   inp = " "
  
   wordsfreq = {}
   pair = {}
  
   for line in words:
       #Add them
       inp += line + " "
   for line in words:
      
       split = line.split(" ")
      
       for word in split:
      
           if word.lower() not in wordsfreq.keys():
          
               wordsfreq[word.lower()] = 1
              
           else:
          
               #Increae it
               wordsfreq[word.lower()] += 1
      
   fIndex = inp.find(str)
      
   if(fIndex == -1):
       return None
      
   # What remains
   text = inp[(fIndex + len(str)):]
      
   split = text.split(" ")
  
   wordsfreq.pop(str, None)
  
   for word in wordsfreq.keys():
  
       count = 0
      
       for topword in split:
           if topword == word:
               count += 1
      
       pair[word] = count
      
      
   keys = list(pair.keys())
   values = list(pair.values())
   maxWord = keys[values.index(max(values))]

   return maxWord

#Note Words is a list in load() method

  

Input text (a file):
banana peach coconut peach pear banana peach apple peach pear apple coconut apple coconut peach pear apple apple peach pear pear apple banana banana banana banana coconut pear apple peach peach apple peach pear coconut apple apple coconut banana peach pear pear apple pear apple pear banana peach coconut apple coconut

Getting common pair for 'apple pear Getting common pair for 'pear apple Getting common pair for 'banana" apple Getting common pair for 'orange' - should be None None should be coconut or peach should be apple should be peach

Answer 1

Python 3.6.1 (default, Dec 2015, 13:05:11) [GCC 4.8.2] o main.py Commonpair method def commonpair (lastWord) global words freq 17 linux 18 data.txt 'hanana: 8. Dcach': 11. 'coconut': 8, 'per 11, 'apple' 13 {' banana': 8, 'peach': 11, 'coconut': 8, 'per 19 20 we need to find the word which occurs most frequenctly after last one. if lastword not in words freq: 21 22 peach 2 - return None ana': 8, 'peach ach 11, 'coconut' 8 24 lastFreq wordsfreq [lastWord] 25 'coconut': 8) 26 coconut now find words having more freq than this, or ties higher Freq - k: v for k, v in wordsfreq.items if print (higherFreq) 27 <- lastFreq and k lastWord) 28 None 25 if len(higherFreq) 0: .. return None from above dictionary, just take the word with minimum freq return max(higherFreq.keys), key-lambda k: higherFreq[k] ) print (commonpair ('apple') 37 print print (commonpair(pear)) 38 35 print 40 print (commonpair('banana')) 41 42 print print (commonpair('orange)) 43

# first read the words from file.

wordsfreq = {}

# change below for the name of your file
for line in open('data.txt'):
        for w in line.split(" "):
                w = w.lower()
                wordsfreq[w] = wordsfreq.get(w, 0) + 1

# now our dictionary is ready.
print('Frequency of words: ')
print(wordsfreq)



#Commonpair method
def commonpair(lastWord):
        global wordsfreq

        # we need to find the word which occurs most frequenctly after last one.
        if lastWord not in wordsfreq:
                return None
        
        lastFreq = wordsfreq[lastWord]

        # now find words having more freq than this, or ties
        higherFreq = {k: v for k, v in wordsfreq.items() if v <= lastFreq and k != lastWord}
        print(higherFreq)

        if len(higherFreq) == 0:
                return None

        # from above dictionary, just take the word with minimum freq
        return max(higherFreq.keys(), key=lambda k: higherFreq[k])

print(commonpair('apple'))
print()
print(commonpair('pear'))
print()
print(commonpair('banana'))
print()
print(commonpair('orange'))

please try above code.. although the code output do not match the expected output exactly.. But i have coded it very cleanly.. it seems there is some issue in the input file.. Let me know if any issues.