When we carry out a chi-square goodness-of-fit test for a normal distribution, the null hypothesis states...
When we carry out a chi-square goodness-of-fit test for a normal distribution, the null hypothesis states that the population:
a) does not have a normal distribution.
b) has a normal distribution.
c) has a chi-square distribution.
d) does not have a chi-square distribution.
e) has k − 3 degrees of freedom.
Homework Answers
From the given information,
Answer is B
When we carry out a chi-square goodness-of-fit test for a normal distribution, the null hypothesis states that the population has a normal distribution.
Add Answer to:
When we carry out a chi-square goodness-of-fit test for a normal
distribution, the null hypothesis states...
When we carry out a chi- square goodness-of-fit test for a normal distribution, the null hypothesis...
When we carry out a chi- square goodness-of-fit test for a normal distribution, the null hypothesis states that the population Does not have a normal distribution Has a normal distribution Has a chi-square distribution Does not have a chi-square distribution Has k-3 degrees of freedom
The chi-square goodness of fit test can be used when: Select one: a. We conduct a...
The chi-square goodness of fit test can be used when: Select one: a. We conduct a multinomial experiment. b. We perform a hypothesis test to determine if a population has a normal distribution. c. We perform a hypothesis test to determine if two population variances significantly differ from each other. d. We conduct a binomial experiment. The x statistic from a contingency table with 6 rows and five columns will have Select one: a. 24 degrees of freedom b. 50...
10.00 points When we carry out a chi-square test of independence, the alternate hypothesis states that...
10.00 points When we carry out a chi-square test of independence, the alternate hypothesis states that the two relevant classifications O are mutually exclusive. O form a contingency table with rrows and c columns O have (1 - 1)(C-1) degrees of freedom are statistically dependent O O are normally distributed
If I reject the null hypothesis of a Chi-Square Goodness-of-Fit Test, which of the following statement...
If I reject the null hypothesis of a Chi-Square Goodness-of-Fit Test, which of the following statement best summarizes my conclusion? There is sufficient evidence to conclude that the two variables are independent. There is sufficient evidence to conclude that the two variables are associated. There is not sufficient evidence to conclude that my proposed distribution does not fit the population. There is sufficient evidence to conclude that my proposed distribution does not fit the population.
The test statistic for goodness of fit has a chi-square distribution with k - 1 degrees...
The test statistic for goodness of fit has a chi-square distribution with k - 1 degrees of freedom provided that the expected frequencies for all categories are a. 10 or more. b. k or more. c. 2k. d. 5 or more.
Assume that a Chi-square test was conducted to test the goodness of fit to a 3:1...
Assume that a Chi-square test was conducted to test the goodness of fit to a 3:1 ratio and that a Chi-square value of 2.62 was obtained (Table value is equal to 3.84). Should the null hypothesis be accepted? How many degrees of freedom would be associated with this test of significance?
In performing a chi-square goodness-of-fit test for a normal distribution, a researcher wants to make sure...
In performing a chi-square goodness-of-fit test for a normal distribution, a researcher wants to make sure that all of the expected cell frequencies are at least five. The sample is divided into 7 intervals. The second through the sixth intervals all have expected cell frequencies of at least five. The first and the last intervals have expected cell frequencies of 1.5 each. After adjusting the number of intervals, the degrees of freedom for the chi-square statistic is O 2 3...
When Chi-square distribution is used as a test of independence, the number of degrees of freedom...
When Chi-square distribution is used as a test of independence, the number of degrees of freedom is related to both the number of rows and the number of columns in the contingency table. Select one: True False Question 2 Answer saved Points out of 1.000 Flag question Question text A goodness of fit test can be used to determine if membership in categories of one variable is different as a function of membership in the categories of a second variable...
When using a chi-square goodness-of-fit test with multinomial probabilities, the rejection of the null hypothesis indicates...
When using a chi-square goodness-of-fit test with multinomial probabilities, the rejection of the null hypothesis indicates that at least one of the multinomial probabilities is not equal to the value stated in the null hypothesis. O True False
In performing a chi-square goodness-of-fit test for a normal distribution, a researcher wants to make sure...
In performing a chi-square goodness-of-fit test for a normal distribution, a researcher wants to make sure that all of the expected cell frequencies are at least five. The sample is divided into 7 intervals. The second through the sixth intervals all have expected cell frequencies of at least five. The first and the last intervals have expected cell frequencies of 1.5 each. After adjusting the number of intervals, the degrees of freedom for the chi-square statistic is ____. 2, 3,5,...
The chi-square goodness of fit test can be used when: Select one: a. We conduct a multinomial experiment. b. We perform a hypothesis test to determine if a population has a normal distribution. c. We perform a hypothesis test to determine if two population variances significantly differ from each other. d. We conduct a binomial experiment. The x statistic from a contingency table with 6 rows and five columns will have Select one: a. 24 degrees of freedom b. 50...
10.00 points When we carry out a chi-square test of independence, the alternate hypothesis states that the two relevant classifications O are mutually exclusive. O form a contingency table with rrows and c columns O have (1 - 1)(C-1) degrees of freedom are statistically dependent O O are normally distributed
If I reject the null hypothesis of a Chi-Square Goodness-of-Fit Test, which of the following statement best summarizes my conclusion? There is sufficient evidence to conclude that the two variables are independent. There is sufficient evidence to conclude that the two variables are associated. There is not sufficient evidence to conclude that my proposed distribution does not fit the population. There is sufficient evidence to conclude that my proposed distribution does not fit the population.
In performing a chi-square goodness-of-fit test for a normal distribution, a researcher wants to make sure that all of the expected cell frequencies are at least five. The sample is divided into 7 intervals. The second through the sixth intervals all have expected cell frequencies of at least five. The first and the last intervals have expected cell frequencies of 1.5 each. After adjusting the number of intervals, the degrees of freedom for the chi-square statistic is O 2 3...
When using a chi-square goodness-of-fit test with multinomial probabilities, the rejection of the null hypothesis indicates that at least one of the multinomial probabilities is not equal to the value stated in the null hypothesis. O True False
Most questions answered within 3 hours.
-
2. Boris recently synthesized an explosive compound he named
Badenoughium. The molecular formula for Bdenoughium is...
asked 2 hours ago -
5. A car decelerate evenly from a velocity of 50mph until rest
in a distance of...
asked 2 hours ago -
IN HTML Programming
1. Write a script that inputs integers (one at a time) and
passes...
asked 2 hours ago -
A dentist uses a mirror to examine a tooth that is 0.75 cm in
front of...
asked 2 hours ago -
You set up a 100,000 line of credit for the business on 1/1/X8,
annual interest is...
asked 2 hours ago -
What is the measurement uncertainty of a pan balance? How did you
get that?
asked 2 hours ago -
Suppose four firms have market shares of 30%, 30%, 20% and 20%.
What is the Herfindahl-Hirschman...
asked 3 hours ago -
IBT Industrial Solutions produces forty units of rack and pinion
type steering gears during an eight...
asked 3 hours ago -
The Ksp for PbI2 is 9.8×10−9 . Will PbI2 precipitate if 2.5 mL
of 0.0025 M...
asked 3 hours ago -
- Write a Person Constructor that initializes `name` and
`age` from arguments.
- All instances of...
asked 3 hours ago -
What is the meaning of the statement: In acid-base catalysis,
acid catalysis involves partial proton transfer...
asked 3 hours ago -
Polo Publishers purchased a multi-color offset press with terms
of $65,000 down and a noninterest-bearing note...
asked 3 hours ago