Question

In performing a chi-square goodness-of-fit test for a normal distribution, a researcher wants to make sure that all of the expected cell frequencies are at least five. The sample is divided into 7 intervals. The second through the sixth intervals all have expected cell frequencies of at least five. The first and the last intervals have expected cell frequencies of 1.5 each. After adjusting the number of intervals, the degrees of freedom for the chi-square statistic is O 2 3 5 O 7 When using simple exponential smoothing, the value of the smoothing constant a cannot be Onegative O greater than zero. greater than 1 99. negative or greater than 1

Answer 1

Answer:

Given that:

The degrees of freedom in a statistical calculation represent how many values involved in a calculation have the freedom to vary.

so degree of freedom = 2(as the first and the seventh interval )

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