Question

An electron with an initial velocity v0 = 2.30×105 m/s enters a region 1.0 cm long where it is electrically accelerated (see the figure). It emerges with velocity v = 5.10×106 m/s. What was its acceleration, assumed constant? (Such a process occurs in the electron gun in a cathode-ray tube, used in television receivers and oscilloscopes.)

Answer 1

V2 - U2 = 2 a s

( 5.1 * 10⁶ )² - (2.3* 10 ⁵)² = 2 * a * 0.01

26.01 * 10 ¹² - 5.29 * 10¹⁰ = 0.02 * a

a = 2595.71 * 10¹⁰ / 0.02

a = 129785.5 * 10¹⁰

a = 1.2978 * 10¹⁵ m/s2