Question

Now two forces are applied to the cart with two different springscales as shown below. The spring scale F₁still reads 10.5 N.

The cart now moves toward the right with an acceleration toward theright of 2.50 m/s². What does spring scaleF₂ read?

C) Again two forces are applied to the cartwith two different spring scales as shown below. The spring scaleF₁ still reads 10.5 N.

The cart moves with a constant velocity toward the right.What does spring scale F₂ read?

D) Again two forces are applied to the cartwith two different spring scales as shown below. The spring scaleF₁ still reads 10.5 N.

The cart moves toward the left with an acceleration toward theleft of 2.50 m/s². What does spring scaleF₂ read?

Answer 1

F 1 = 10.5 N

Accleration a = 2.5 m / s^ 2

we know ( F 1 - F 2 ) = m a

from this F 2 = F 1 - ma

where m = mass of the cart

( C ) . It moves constant velocity that is accleration =0

So, F 2 = F 1

           = 10.5 N

(D ) . It moves left side with an accleration a = 2.5 m / s ^2

So, net force F 2 - F 1 = m a

from this F 2 = F 1 + m a

Answer 2

The two forces acting to cause an acceleration are:




from the previous question m=3.23077kg so



c)There is no acceleration so the forces must be balanced


d)The two forces acting to cause an acceleration are:

Answer 3

(a) From the Newtons second law

                           F1 - F2 = ma

                                  F2 = F1 - ma

(b) if the cart moves with constant velocity thenaccelaration is a = 0 m/s²

              From the Newtons second law

                           F1 - F2 = ma

                            F1- F2 = 0

                                   F1 = F2

  (c)  From the Newtons second law

                           F2 - F1 = ma

                                  F2 = F1 + ma