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Calculate the Reynolds number, Re- (2rpv)/ n, for the following situations and decide whether the flow of fluid around them is laminar or turbulent. Then calculate the frag force using the appropriate formula. For the radius, use r 2(Area/perimeter) which, for a circle, gives the radius. Densities and viscosities are in the table on page 2. Also, to keep things uniform, we will use the boundaries for laminar and turbulent flow from Engineers Toolbox, also on pg. 2 [1] A car with 1.5 m2 square cross-sectional area moving at 2 m/s through air at 20°C. 2] Same car at 27 m/s (just over 60 mph) [3] The fastest human swimmers can travel at 2.3 m/s. Use this speed for a swimmer underwater (an overestimate) and use a radius of 0.7 meters 4] For a blue whale, a fast speed is 13.9 m/s and the radius for their cross-section is 1.9 meters Calculate the Reynolds number.[51 Many microscopic organisms and small multi-cell creatures who live (and move) in water move by using flagella or shorter cilia moving in a wavelike fashion to push against the water. A large paramecium can have a radius of 0.5 mm. and can move at speeds up to 1mm/s. Calculate the Reynolds number for these wee beasties1 water 20°C air 20°C peanut butter density (kg/m3) 1000 1.204 1090 viscosity (cp mPa.s 1.03 02217 250,000 From Engineering Toolbox: The Reynolds Number can be used to determine if flow is laminar, transient or turbulent. The flow is . laminar when Re <2300 . transient when 2300 Re< 4000 . turbulent when Re 4000 Speeds of microorganisms: http://hypertextbook.com/facts/2000/RossKrupnik.shtml 1. Antony Van Leeuwenhoek coined this term after viewing the first microorganisms through his home-made microscopes These are only simple estimates, they ignore significant details, such as the shape of the front of the object. At this level, a cylinder and a bullet with the same cross-sectional area have the same Reynolds number and drag force, which is absolutely false. Taking these details into account requires either a lot more advanced treatment of fluid mechanics or a lot of careful experimentation.

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Answer #1

1) As the cross section is square, we will use hydraulic diameter

for square, d = 4A/P

so,

d = 4 * 1.5 / 4*1.2247

d = 1.2247 m

so,

NOTE - WHAT ARE THE UNITS OF VISCOSITY IN TABLE ??? IS IS mPa.s (does m here stands for milli..?.)

Reynold's number = 1.204 * 2 * 1.2247 / 0.02217E-3

Reynold's number = 1.33e5

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(2) when v = 27 m/s

Reynold's number = 1.204 * 27 * 1.2247 / 0.02217E-3

Reynold's number = 1.8e6

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3) for swimmer,

Reynold's number = 1000 * 2.3 * 1.4 / 1.03e-3

Reynold's number = 3.12e6

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4) for whale

Reynold's number = 1000 * 13.9 * 2 * 1.9 / 1.03e-3

Reynold's number = 5.12e7

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