Chapter 13, Question 25 The following data are obtained for the decomposition of N2O5 at 45°C:...
The decomposition of N2O5 is described by the following equation. 2N2O5(g) → 4NO2(g) + O2(g) If the rate constant is 2.50 × 10−4 s−1, what is the half-life of this reaction?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.50×10−2 mol of N2O5(g) in a volume of 1.8 L . Part A: How many moles of N2O5 will remain after 4.0 min ? Part B: How many minutes will it take for the quantity of N2O5 to drop to 1.9×10−2 mol ? Part C: What is the half-life of N2O5 at 70∘C?
6) The rate constant for the first-order decomposition of N2O5 in the reaction 2N2O5(g) → 4NO2(g) + O2(g) is k=3.38 x 10-5 s-1 at 25°C. What is the half-life of N2O5? What will be the total pressure, initially 88.3 kPa for the pure N2O5 vapour, (a) 10 s, (b) 10 minutes after initiation of the reaction?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.40×10−2 mol of N2O5(g) in a volume of 2.1 L. a) How many moles of N2O5 will remain after 7.0 min? b) How many minutes will it take for the quantity of N2O5 to drop to 1.6×10−2 mol?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.30×10−2 mol of N2O5(g) in a volume of 1.5 L . a. How many moles of N2O5 will remain after 6 min ? b. How many minutes will it take for the quantity of N2O5 to drop to 1.9×10−2 mol ? c. What is the half-life of N2O5 at 70∘C?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.00×10−2 mol of N2O5(g) in a volume of 2.0 L . How many moles of N2O5 will remain after 7.0 min? How many minutes will it take for the quantity of N2O5 to drop to 1.6×10−2 mol? What is the half-life of N2O5 at 70∘C?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.60×10−2 mol of N2O5(g) in a volume of 2.3 L Part A How many moles of N2O5 will remain after 4.0 min ? Part B How many minutes will it take for the quantity of N2O5 to drop to 1.8×10−2 mol ? Part C What is the half-life of N2O5 at 70∘C?
The decomposition of N2O5 can be described by the equation 2N2O5(soln)⟶4NO2(soln)+O2(g) Consider the data in the table for the reaction at 45 ∘C in carbon tetrachloride solution. ? (?) [N2O5] (?) 0 1.934 225 1.679 556 1.363 795 1.173 Given the data, calculate the average rate of reaction for each successive time interval. A) What is the average rate of reaction for the time interval from 0 s0 s to 225 s? B) What is the average rate of reaction...
The following data are obtained for the decomposition of N,Og at a certain temperature: 2N205(9) - 4NO2(g) + O2(9) Time(s) N205 (atm) 0 2.40 200 2.13 400 1.88 600 1.67 800 1.48 Find the rate constant kobs for this first-order decomposition reaction. (Enter in sec-1) Submit Answer Tries 0/99
1A. The decomposition of dinitrogen pentoxide in carbon
tetrachloride solution at 30 °C N2O5 2 NO2 + ½ O2 is first order in
N2O5 with a rate constant of 4.10×10-3 min-1. If the initial
concentration of N2O5 is 0.510 M, the concentration of N2O5 will be
M after 402 min h
1B. The gas phase decomposition of phosphine at 120 °C
PH3(g)1/4
P4(g) + 3/2 H2(g)
is first order in PH3
with a rate constant of 1.80×10-2
s-1.
If the...