Question

A triangle with equal sides of length 10 cm has 2.5-nC charged objects at each corner Determine the direction of the electrical force exerted on the object at the top corner due to the two objects at the horizontal base of the triangle. vertically downward O horizontally rightward O horizontally leftward O vertically upward Determine the magnitude of the electrical force exerted on the object at the top corner due to the two objects at the base of the triangle. Express your answer with the appropriate units. F-Valu Units Submit RequestAnswer

Answer 1

Horizontal C component get cancelled as in opposite direction only vertical components add up Net force vertically up ward Force due to each charge F_e k q_1 q_2/r^2 r = 0.1 m q_1 = q_2 = 2.5 n C k = 8.99 times 10^9 F = 2.5 times 2.5 times 10^- 18 times 8.99 times 10^9/(0.1)^2 rightarrow 5.618 times 10^^- 6 N F sin 30 degree = F sin 30 degree Net force = F cos 30 degree + F cos 30 degree = 2 F cos 30 degree = 2 times 5.618 times 10^- 6 times squareroot 3/2 rightarrow 9.7316 times 10^- 6 N Net force = 9.7316 times 10^- 6 N