Here we are given that a random sample of 25 people have average 160 pound and standard deviation 20 pounds then the standard deviation of population mean will be 20/5 that is 4 pound and average vof population mean will be 160 pound.
a random sample of 25 people whose population average weight is 160 pounds with a standard...
In a random sample of 64 trout, the average weight is 3 pounds, with standard deviation s = .5 pounds Find: sample mean standard error of the sample mean margin of error 95% 95% confidence interval for the population mean, µ:
A sample of 25 adult elephants had a mean weight of 9500 pounds with a sample standard deviation of 150 pounds. The population distribution is normal. The margin of error for 99% confidence interval calculation is equal to: a, 61.9 b. 77.3 c. 83.9 The 99% confidence interval for the population mean is equal to: a, (9416.1, 9583.9) b. (9422.7, 9577.3) c. (8438.1, 9561.9)
(2 Points) A random sample of size n = 25 is taken from a population with mean u = 530 and standard deviation o = 100. Then the sampling distribution of the sample mean X has normal distribution with mean 530 and standard deviation 20 has normal distribution with mean 530 and standard deviation 100 has normal distribution with mean 530 and standard deviation 2 has normal distribution with mean 530 and standard deviation 4
A test on a random sample of 50 water balloons yielded a sample average weight of 1.2 pounds. Prior studies have shown that the population standard deviation is 0.2 pounds. Assume that water balloon weight is normally distributed. Construct a 95% confidence interval of the population mean?
The weight (in pounds) for a population of school-aged children is normally distributed with a mean equal to 133 ± 21 pounds (μ ± σ). Suppose we select a sample of 100 children (n = 100) to test whether children in this population are gaining weight at a 0.05 level of significance. a. What are the null and alternative hypotheses? b. What is the critical value for this test? c. What is the mean of the sampling distribution? d. What...
Suppose a random sample of n = 25 observations is selected from a population that is normally distributed with mean equal to 106 and standard deviation equal to 15. (a) Give the mean and the standard deviation of the sampling distribution of the sample mean x̄. mean= standard deviation= (b) Find the probability that x̄ exceeds 115. (Round your answer to four decimal places.) (c) Find the probability that the sample mean deviates from the population mean μ...
please help! stabdard error! The weight of people in Ozark, Arkansas is normally distributed with a population mean of 185 pounds with a population standard deviation of 25 pounds. 1. What is the standard error of the mean for a random sample of 16 people from Ozark, Ark? 2. How many people must be sampled to decrease the standard error of the mean to 5? 3. What is the probability of the average weight of 16 people in Ozark picked...
A sample of 8 adult elephants had an average weight of 12,300 pounds. The standard deviation for the sample was 22 pounds. Find the 95% confidence interval of the population mean for the weights of adult elephants.
5.4.1 Question Help A population has a mean = 141 and a standard deviation o = 28. Find the mean and standard deviation of the sampling distribution of sample means with sample size n = 40. The mean is :-), and the standard deviation is 0;=0 (Round to three decimal places as needed.) 5.4.2 Question Help A population has a meanu - 74 and a standard deviation = 8. Find the mean and standard deviation of a sampling distribution of...
A random sample of size 137 was taken from a population with a population mean 25 and a population standard deviation 5. Determine each of the following about the sampling distribution of the sample mean. Round your answer to at least 3 decimal places where appropriate. a) μx_= b) σx_= c) Can we conclude that the sampling distribution of the sample mean is approximately normal? YesNoClick for List