Question

can you give the IUPAC names pls and if they are E or Z stereoisomers

OH e

Answer 1

longest carbon chain has 4 carbons, the rootword is "but" Since in the given compound one double bond present at 2 nd carbon atom, the suffix is "ene". Here methyl group is substitutent at 2 nd carbon atom .Alcohol is functional group at first carbon atom. High priority groups are present same side at double bonded carbon atom(Z -configuration). (Z)-2-methylbut-2-en-1-ol b) High priority groups are present same side at double bonded carbon atom(z -configuration). (Z)-3-(2-fluoroethylhept-2-ene OH High priority groups are present opposite side at double bonded carbon atom(Z -configuration). (E)-3-(tert-butyl)pent-3-en-1-ol 192kbesugihan santos High priority groups are present opposite side at double bonded carbon atom(z -configuration). (E)-pent-2-en-3-ylcyclopropane

To give the E and Z nomenclature to the double bond, if same priority number (molecular weight wise) on the same side then that alkene is Z, if same priority numbers are in opposite side then the configuration of alkene is E This side first atom is carbon on both side, isopropyl gets first priority than methyl first priority groups are on same side, hence olefin configuration is Z F gets 1 because it's atomic number is 9 (greater than C)