Homework Answers
net horizontal force
Fx = - 9 cos 29 - 7 cos 70 + 5 cos 40
Fx = - 6.435 kips
net vertical force
Fy = 5 sin 40 + 7 sin 70 + 9 sin 20
Fy = 12.87 kips
=========
a)
net magnitude of force
F^2 = Fx^2 + Fy^2
F = 14.39 kips
========
b)
direction
phi = 180 - arctan ( 12.87 / 6.435)
phi = 116.565 (ccw from +x axis)
=======
Comment in case any doubt, will reply for sure.. Goodluck
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