Question

6. At a wedding the 2m tall bride throws her bouquet with a velocity vo 25m/s at an angle 37° above the horizontal. It is caught by a friend of height 1.5m. How long is the bouquet in flight and how far did it go horizontally? What was its maximum height above the ground?

Answer 1

a delta H = v_0 sin theta t - 1/2 gt^2 (1.5 - 2) = 25 sin 37 degree times t - 1/2 times 9.8 times t^2 t = 3.1 sec b H_max = H_0 + (v_0 sin theta)^2/2g = 2 + (25 sin 37 degree)^2/2 times 9.8 = 13.5m.