Question

1. 2. Numerical Problems An aeroplane is flying horizontally at a speed of 100 m's releases a bomb at a height of 500 m. Find (1) the time taken by the to reach the ground. (ii) The horizontal distance where the bomb strikes the ground A bomb is dropped from an aeroplane when it is directly above a target at a height of 1500 m. If the speed of the aeroplane in the horizontal direction is be 540 km/h, calculate the distance by which the bomb miss the target. A plane flying horizontally at a height of 1000 m with a speed of 900 km/h, releases a bomb from it. Find (a) the time taken by the bomb to reach the ground, (b) the velocity with which it hits the target on the ground and (c) distance of the target. A ball rolls off the edge of a tabletop 1.25 m above the floor and strikes the floor at point 2.5 m horizontally from the edge of the table. Find (1) the time of flight, (ii) the initial velocity of the ball, and (iii) the velocity of the ball just before it strikes the floor. [0.5s,5m/s, 7.1m/s) 3. 5. A body is projected with a velocity 50 m's at an angle 30 with the horizontal. Calculate (a) the maximum height, (b) time of flight, (c) the horizontal range and (d) maximum horizontal range. 6. 7. The ceiling of a long hall is 25m high. What is the maximum horizontal distance that a ball thrown with a speed of 40 m/s can go with out hitting the ceiling of the hall? [150.5m] A cricketer can throw a ball to a maximum horizontal distance of 100 m. How high above the ground can this cricketer throw the same ball? A shot is fired from a gun on the top of a hill 50 m high with a velocity 80 m's at an angle 30° with the horizontal. Find the horizontal distance where the shot strikes the ground. [50m) 8. 9 A stone is thrown from the top of a pillar 20 m high with a velocity 40 m/s, at an angle 30° with the horizontal. Find the horizontal distance where the stone strikes the ground.

Answer 1

classmate Date Page 0 u lo mis H=500 m (i) R = uT 2H & IE .. I= 2(500) go8 T= 10.lo Sec R = (10010) (160) m R = 1010.15 m H = 1500 m ; u= 150 m/s 540 km/h 2(150) 150 gog 121 R = u - m of R = 2624 .45 m = 2.62 km . H =1000 m u= 900 km/h - 250 mls 21 TE = I= 14.29 sec (6) Vv Vy. - u=900 km/h = 250 mls JI (9:8) (14.29) mjs = 140 mls. (250)² + (140)² m/s Vz =

classmate Poge 286.53 mis (C) R UT 250) (14.29) m 3571.43 in = 3.57 km R M T= 21 2(1.25) sec ob 9.8 = 0.50 sec R=UT ㅋ u = R T 2 2.5 0.51 m/s u 4.95 mls u= 5.0 m/s V 7 5.0 m/s = (9.8) (0-5) misa Vy = gT mis 4.9 2 vx tvy Film's Fol m/s 5 u=50mis = 30° ; 2 2 u sln to (a) H = (50) sin(300) 249.87 28 H = 31.89 m

classmate Date Page (b) R = utsin (20) g toj sin (60) R = m go8 R 220.92 m 2 W (C) Remax (50) go8 m مه Rmax 255.1 m H = 25 me utsino -25 29 29 2 & Romana u sin20 g .. u= 90 m/s sinze 25*2(9.8) 166 33.36° 12 R = (40? stim (66.72) m 9.8 R T50 m

classmate Date Page 7 RE 100m u²sin 20 » Rm u² 0=45) 40 g & H too sin (45)m 2g H = 25 m h =50m U= so mis jos 30° y = h tu tano g x² 2u²costo 50 +(97413) * 9.8 x² 2(640) (30) 0 2 0.0010208 a 0.5774a 50 Ź x = 641.9 m RE 642 m Again y = h tatano g 2u²on20 2 2 o.co 1083 x² - 0.5774 a - 20 o xa 170 : 2 m R 170.2 m