Question

In the circuit shown in Figure 6(b), an emf source E = 12 V and resistance r = 0.3.2 is connected to two resistors R1 = 1.52 and R2 = 1.212. Two capacitors C1 = 0.05 uF and C2 = 0.02 uF are connected in parallel to the resistors, and switch S is open. ię RB + + RB Figure 6(b) Calculate the current in the circuit and the charges Q1, Q2 on the capacitors after a long time. ANS: ANS: (ii) ANS: What values do these quantities take if switch S is closed and after another long period of time?

Answer 1

liven, emf souste CE)= 12v Resistance (6 = 0.3 R2 = 1.2 - Ri= 1152 C= 0.05 Mf (2=0.02 Mf (o) after 3 3 current (E) = long period of = 12 = time is 12 = 4 A 8tRitha 0.3+1.2+105 n in е series, (а не I = 4A / AN - and both capacitor are connected - go, Chare on bo#m Cape o kr wiн so, Q, = Q₂ = 0. or. lo +9 = {-ir. = 12 - 4x0.3 + > 0 0.05x10-6 q 000 2 X10-6 1 » 200 + 50o = 10088106 P = 0.1542x70 DE or IP,=Q2 = 00 1542 Mc. ] Ane 1. ii) when switch is closed period of time potential to that of Ci x to that of Ra then also after a long diff. across Ro egung that of R2 equal so -

Q - Ihr I RI 92 (2 so ohne - IR - I 9, = 4(15) 1000s), Q2 = IR 2 C2, To - 0.3 kc. li og = 4 C102) (0.02) P=0.096 ich am 10,5 02 dichas (Please rate the answer!)