Question

The circuit of (Figure 1) is a square 20 cm on a side. The magnetic field increases steadily from 0T to 0.55 T in 13 ms Part A For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution What is the current in the resistor during this time? Express your answer with the appropriate units. Value Units Figure 1 of 1 > Submit Request Answer 200 < Return to Assignment Provide Feedback 9.0 V

Answer 1

magnitude of emf induced is given by,

e = d($\phi$)/dt

$\phi$ is the magnetic field flux, = B*A

e = A*(dB/dt)

e = a²(dB/dt)

e = 0.2²*(0.55/0.013)

e = 1.692 Volts

and from ohm's law we know that,

V = iR

and the current produced due to the change in flux is in the same direction as current due to the existing battery

hence

V+e = iR

9 + 1.692 = i*20

i = 0.5346 Amp