Question

Constants Two point charges q1 and q2 are held in place 4.50 cm apart. Another point charge Q-2.00 μC of mass m 4.50 g is initially located 3.00 cm from each of these charges (the figure(Figure 1)) and released from rest. You observe that the initial acceleration of point charge Q is a 324 m/s2 upward, parallel to the line connecting the two point charges. Part A Find qi and q2 Enter your answers numerically separated by a comma. View Available Hint(s) Figure 1 of 1 Submit Previous Answer X Incorrect; Try Again; 2 attempts remaining 4.50 cm Provide Feedback

Answer 1

Part A

g2 is negative

$F_{AB}=krac{q_AQ_B}{r_{AB}^{2}}$

$F=2F_{up}$

0.729 N Fup - 2

Force between Q and qi is

4.5 cmn cos α = 0.75 Fo. 3 cm

Using Coulombs law:

$substituting:F_{Q,q_1}:and:solving:for:q_1:$

gi = 4.86 × 10-8 C

$q_2:should:be:$

g-=-4.86 × 10-8 C