Question

Step 2: Show the conversions required to solve this problem and calculate the grams of Cl.. 76.8 g AICI, X Answer Bank 26.98 g AI 1 mole A1 2 moles Al 70.90 g CI 1 mole C1, 3 moles CI, 133.33 AICI, 1 mole AICI, 2 moles AICI,

Answer 1

To find the mass of CI, Given that 76.8g of AICI: Balanced chemical reaction 2Al(s) +3a (8) 2A1C3() Step 1: moles of AlCl3, moles of C, grames of AICI, grames of Ala, moles of AICI, Step 2 1m ole of Aid, 3moles of a 76.8g of AICI, 133.33g of AlCl3.2moles of A1C1, Hence the mass of Cl, = 61.38 grames of Cl -=g of a . moles of a, 70.90g of Cl, _ 612 2 = 61.38 of C1 1mole of C1,

To find the moles of H, Given that 80.4g of water (H20) First find the moles of H,0 moles = __mass molarmass molarmass of 1,0 =18.02 g/mol moles=_80.49 18.02g/mol = 4.47mol find the moles of H 1mole of H, Ogives 1 mole of H, Therefore moles of H, = 4.47mol Hence the moles of H, = 4.47mol