A1. For problem 21.57, write a formula for the position vector of the electron as a function of time, r⃗(t)r→(t), using unit vector ("i-hat" and "j-hat") notation. Assume the electron starts at the origin of your coordinate system at t = 0, so r0→=0iˆ+0jˆ. (Hint: Use equation 3-13b from the textbook.)
--- Hint
answer) force on the electron is given by
F=eE..........1)
from newtons second law we have
F=me*a.......2
so we have
eE=me*a
a=eE/me
now we have x and y components of the acceleration is
ax=eEx/me=-1.6*10-19*2*104/9.1*10-31kg=-3.5*1015m/s2
ay=eEy/me=-1.6*10-19*8*104/9.1*10-31=-1.4*1016m/s2
the vector acceleration of the electron=-3.5*1015i-1.4*1016j (answer)
b) now for than angle we have
Vx=vxo+axt=8*104m/s+(-3.5*1015*1*10-9)=-3.4*106m/s
vy=vyo+ayt=0-1.4*1016*10-9=-1.4*107m/s
so tan =vy/vx
=tan-1(-1.4*107/3.4*106)=76.3
but since the initial velocity is going upwards
the angle =180+76.3=256.3o
so the answer is 256o or 256.3o
A1. For problem 21.57, write a formula for the position vector of the electron as a...
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