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Perform calculations using Gay-Lussacs Law Question A gas in a sealed container has an initial pressure of 125 kPa at 25.0°

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Gay lusac law pressure is directly absolute temperature At constant volume, the proportional to the of the gas PaT Р= КГ K isP, = 125kpa Tr= 25+973.15 = 298.15k Pq = 150 kPa Tg = ? 125 kPa 998-15 Та 150kpa 150kPa x 298.15k 125 kPa Tz = 38000 357.78 k

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