Question

Compound E: C7H6O3

Hi, can someone please help me with the following questions?

Draw a molecule that combines both of the above fragments. Show ALL hydrogen What is the molecular formula of the molecule you just drew? (Use the following format: CXHYOZ, where X, Y, and Z are numbers.) What is the molecular formula of the molecule you just drew? (Use the following format: CXHYOZ, where X, Y, and Z are numbers.) The difference between the formula you just wrote out and the molecular formula of compound E is one atom. That atom is part of the functional group that also accounts for the singlet at 5.4 ppm in the 1H NMR spectrum. What is the name of that functional group? How will you combine the fragment you drew above with this functional group? To get to the correct structure of Compound E you will have to consider carefully the splitting patterns in the 1H NMR spectrum.

Answer 1

NOT in the compound E amine and nitrile

Answer 2

24)

a) Double bond equivalent can be calculated as

$DBE = C - \frac{H}{2} + \frac{N}{2} +1$

DBE = 7 - (6/2) + 0+1 = 5

b) due to absence of nitrogen the following groups are definitely not present

Nitrile and amine

Also, alkyne is absent

25)

The NMR signals above 5ppm shows the presence of aromatic ring

25) The singlet at 11 ppm is due to carboxylic group

25) The compound could be

он C7HsO2

25) the name of that functional group is : Alcohol (Hydroxyl group)

25) The stucture of given compound E.

OH