Standardization of Sodium Thiosulfate

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Standardization of Sodium Thiosulfate

In one trial of the standardization of a Na2S2O3 solution, a 10.00 mL volume of 5.00×10-3 M KIO3 is pipetted into a 250 mL Erlenmeyer flask. The solution is titratedto the endpoint with 15.23 mL of the Na2S2O3 solution. What is the molar concentration of this sodium thiosulfate solution?

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Answer 1

Answer #1

KIO3 + 6 Na2S2O3 + 6 H+ => KI + 3 Na2S4O6 + 6 Na+ + 3 H2O

Moles of KIO3 = volume x concentration of KIO3

= 10.00/1000 x 5.00 x 10^-3 = 5.00 x 10^-5 M

Moles of Na2S2O3 = 6 x moles of KIO3

= 6 x 5.00 x 10^-5 = 3.00 x 10^-4 mol

Concentration of Na2S2O3 = moles/volume in L of Na2S2O3

= 3.00 x 10^-4/0.01523

= 0.0197 M = 1.97 x 10^-2 M

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Answer 2

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Standardization of Sodium Thiosulfate

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