In each reaction box, place the best reagent and conditions from the list below. are on...
In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below. You are correct that the third step is a reduction of 2-pentyne. But H2 with a platinum catalyst will reduce it to pentane, while you need an alkene for the next step. NaNH H3C OH HO 2) CH3CH2Br CEC H3C CH3. H3C H2, Pt HO 4) KMno 4, NaOH, H20, cold BH3...
In each reaction box, place the best reagent and conditions from the list below In each reaction box, place the best reagent and conditions from the list below. Br2 H2O, H2SO4(cat.) H202, NaOH, H2O PBr3 BH3/THF H2, Lindlar's catalyst CH3CH2OH CH3COO- NaNH2 (excess) H2, Pt
In each reaction box, place the best reagent and conditions from the list below. If you reduce the alkyne in step 3, you would need six steps overall to produce the final carboxylic acid. In each reaction box, place the best reagent and conditions from the list below. If you reduce the alkyne in step 3, you would need six steps overall to produce the final carboxylic acid.
In each reaction box, place the best reagent and conditions from the list below. pling In each reaction box, place the best reagent and conditions from the list below. HBr CH3Br H2, Pt Br2 NaOH NaNH BH3 THF NBS, ROOR, hv H2, Lindlar's catalyst H202, NaOH, H20 NaBH4
In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below. Your reagent for the first step is incorrect. This reaction involved a double elimination of HBr to form an alkyne. Which reagent is a strong base capable of carrying out this reaction ?
in each reaction box, place the best reagent and conditions from the list below. Print Calculator Periodic Table of 40 ling Learning lan learning in each reaction box, place the best reagent and conditions from the list below. HECH NaNH2 -CH2 OH NaOH H2. Lindlar's catalyst BH THE H2O2, NaOH, H20 Cros. H2SO4 H20 CH Br H2. Pt CH CHBr NaBHA CH3CH2CH Br Hint
In each reaction box, place the best reagent and conditions from the list below. A reagent may be used more than once.) Each end of the alkyne chain must be lengthened by two carbon atoms. Propyl bromide in step 2 would add three carbons to one end. 1) 2) CHsCH-CH-Br NaNH2 он NaNH2 3) 4) 5) H3O CH3CH2Br CH3Br CH3CH2CH2Br BH3/THF NaOH NaBH4 H2, Lindlar catalyst H3O H202/NaOH CH3CH2CH2CH2Br NaNH2
in each reaction box place the best reagent and conditions from the list below In each reaction box, place the best reagent and conditions from the list below. KMnO_4, NaOH, H_2O, cold H_2 Lindlar's Catalyst CH_3CH_2CH_2Br NaOH, H_2O BH_3/THF CH_3CH_2Br H_2, Pt CH_3Br Na, NH_3 (l) NaBH_4 NaNH_2
In each reaction box, place the best reagent and conditions from the list below. 1) 2) 3) HO CH3Br NaNH2 H2, Lindlar's catalyst H202, NaOH, H2O NaBH4 NBS, ROOR, hv H2, Pt BH3/THF Br2 NaOH
In each reaction box, place the best reagent and conditions from the list below. mu have the right idea for generating an alkyne in the first two steps. Remember that a primary alkyne also reacts with NaNH2 to form the alkylide ion, so with only two equivalents of NaNH2 you will d up with a mixture of some alkylide anion, some unreacted vinyl bromide and probably some unreacted vicinal dibromide. Br2 O 2 equiv. NaNH2 OY BH3/THF 3) 4) H2O2,...