Question

Look at the given IR spectra for compound Z. Determine what kinds of bonds/functional group are present and select present/absent. Alcohol/ Secondary Amine (O-H/N-H) [Select] Carboxylic Acid (O-H) [ Select ] , Primary Amine (-NH2) [ Select] A Alkyne (C-H) [Select] Alkene (=C-H) (Select] Alkane (C-H) (Select] Aldehyde (C-H) (Select ] Triple bond (CC or CN) [Select] A Carbonyl (C=O) (Select] Alkene (C=C) [ Select] Alkane (C-C) [ Select ] 9 Look at the given compounds. Determine if each could have given the above spectrum. It's possible that more than one compound or no compounds could match the spectrum. Compound A Select] be compound Z. Compound B [ Select] be compound Z. Compound C (Select] be compound Z. Compound D (Select ] be compound Z. Compound e ( Select] be compound Z.

Answer 1

IR analysis

the band at 1700 cm^-1 is due to a carbonyl group (-C=O)

the band at 2100 cm^-1 is due to C$\equiv$C or C$\equiv$N stretching

the band at 3300 cm^-1 is due to -NH₂ group

apart from above other functional group are absent