Question

Using the GOODNESS OF FIT TEST, Calculate x2. Use a 0.05 level of significance to test the claim that the age distribution of the Canadian population fits the age distribution of Red Lake Village. The age distribution of Red Lake is based on a random sample of 455 residences. Age Percent of Canadian Population Observed Number in Red Lake Under 5 8% 48 5 to 14 12% 74 15 to 64 65% 287 64 and up 15% 46 Which is the correct Null (H0) hypothesis for a goodness of fit test? A. The variables are independent B. The distribution is different C. The variables are not independent D. The distribution is the same Reset Selection Question 72 of 77 1.0 Points What is the level of significance? Question 73 of 77 1.0 Points What are the degrees of freedom? dk = k-1 Question 74 of 77 1.0 Points Using the level of significance and the degrees of freedom from above and table A-4 in the book find the critical chi-squared value. Question 75 of 77 4.0 Points Find the expected value using the following formula. Round to the tenths place. Expected = np Observed Expected 48 (a) 74 (b) 287 (c) 46 (d) Question 76 of 77 10.0 Points Find the value of chi-square statistics for the sample using the formula: Remember to round O-E and (O-E)2 to the HUNDREDTHS. Remember to round (O-E)2 ÷ E to the THOUSANDTHS. My sample statistic x2: A. 18.133 B. 0.821 C. 4.632 D. 100.446 Reset Selection Question 77 of 77 1.0 Points Based on my answers, I will: A. Accept H0, the Null hypothesis B. Reject H0, the Null hypothesis

Answer 1

shi buton s the same a lstaibuton s diferant SO.03A dPeb43 Caitical Nalue ,y 2 CASom talle) 7.815 pecked Nalue - nP elereene d (on expected C) 36.4 (1.60 134-56 3.696 74 S4.6 19.40 6.893 376.36 281 295-15 3-15 16.56 0.258 46 8.25 -22 25 495.06 7254 12.101 2 Y18.101 Peject to Cautic Shat