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polynomial bo bit + b2 t2 +b3 t3 a) A binary string bobib2b3 is converted to a and is then coded by multiplying by the polyno

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A binary string bobibzb3 is converted to a polynomial b3 t3 + b2 t2 +b1t + bo and is then coded by multiplying by the polynomial t3 + t2 +1. The resulting polynomial is then converted back to a binary string of length seven (7) and then transmitted This string is received as 1100011, with bit order being higher powers of t to the left. Assume that al most one of these seven (7) bits has been corrupted in the transmission process. (Ensure that you have appreciated the correct order of bits in any corresponding polynomial calculations that you perform.

EXPLANATION ::-

(i) Show that indeed an error has occurred in one of the bits

SOL::-

A binary string is converted to polynomial b0 + b1t+ b2t3 . So the operation here are in modulo 2.

1) Let the original string was b1 b2 b3 are assume that no error was done during transmission.

=

Hence the output will be

0 1 0 1 0

      

   

As there is almost one error happend ,error surves happend

(ii What was the correct transmitted string?

SOL::-

Put then  

all other equations takes right position so, that string output is 0 1 0 1 1 1 0.

(iii) Correct the error and recover the original message bob1b2b3.

SOL::-

Original message is 0110.

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