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The cantilever beam shown is subjected to a moment at A and a distributed load that...

The cantilever beam shown is subjected to a moment at A and a distributed load that acts over segment BC, and is fixed at C. Determine the reactions at the support located at C. Then write expressions for shear and bending moment as a function of their positions along the beam. Finally, use these expressions to construct shear and bending moment diagrams

The cantilever beam shown is subjected to a moment

Draw a free-body diagram of the beam on paper. Use your free-body diagram to determine the reactions at support C. Assume positive moments act counterclockwise.

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Answer #1

Draw the free body diagram of the beam: 5 k 120 kip-ft 8 ft 6 ft Apply equilibrium equations: Consider the sum of vertical forces equal to zero. Cy-(5x6)0 C, = 30 kips Take mom ents about A Cy x14)-(5x6x11)-M.+120-0 (30x14)-(5x6x11)-120-M. ?.-210 kipft Consider the section X-X, and 0<x<8 120 kip-ft rft Compute the shear force as follows Shear force at x0 Shear force at x 8 Write the expression for bending moment Bending moment at x= 0 BM4--120 kip-ft Bending moment at x 8 BMB120 kip-ft Consider the section X-X, and 8<x<14 120 k-ft 8 m Write the expression for shear force: Shear force at x = 8 SF-5(8-8) Shear force at x 14 SFc(14-8) -30 k Write the expression for bending moment BM,-120-5(? Bending moment at x-8 5(8-8) BMB120 --120 kip-ft Bending moment at x=14 BMc=-120- ) -210 kipft 2 5 14-8 Draw the shear force diagram 30k Draw the bending moment diagram: -120 k-ft -210 k-ft

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