3. Find the distance traveled by this box when is sides to a sop. Use Newton's...

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Answer 1

Answer #1

Given,

uk = 0.1 ; v = 20 ft/s ; g = 32.2 ft/s^2 ; m = 50 lb

We know from conservation of energy

KE = Ff

FF is the work done against friction

1/2 m v^2 = uk m g d

1/2 v^2 = uk g d

d = 0.5 v^2/uk g

d = 0.5 x 20 x 20/0.1 x 32.2 = 62.11 ft

Hence, d = 62.11 ft

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Answer 2

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