Pressure on the bullet, P = 34500 lb/in2
diameter of the bullet, d = 0.270in
Area of the cross-section of the bullet, A = ( pi/4)*d2 = ( pi/4)* (0.270)2 =0.05726 in2
Force on the bullet, F = P.A = (34500 lb/in2) * (0.05726 in2) =1975.316 lb = (1975.316 * 4.45) N = 8790.15 N (ans)
A rifle bullet whose diameter is 0.270 in. (270) is subjected to a pressure of 34,500...
When a .22-caliber rifle is fired, the expanding gas from the burning gunpowder creates a pressure behind the bullet. This pressure causes the force that pushes the bullet through the barrel. The barrel has a length of 0.61 m and an opening whose radius is 2.8 103 m. A bullet (mass 2.6 103 kg) has a speed of 370 m/s after passing through this barrel. Ignore friction and determine the average pressure of the expanding gas.