As we know that 1 mole of a gas consists of 6.023 x 10^23 atoms
So, 1.0 x 10^23 atoms = (1.0 x 10^23) / (6.023 x 10^23) = 0.166 mole
Assuming the process under constant volume
Cv for ideal gas =12.5 J/ (mol.K)
Amount of thermal energy added to the gas = 11.0 J
So -
μCv dt = 0.166 x 12.5 x dt = 11.0 J
=> dt = 11.0 / (0.166 x 12.5 ) = 5.30 K
Therefore, the new temperature of the gas = 0 + 5.30 = 5.30 deg C.
(Please note that we have considered the temperature 5.30 K is equal to 5.30 deg C, because when finding the difference in temperature, both units kelvin and deg. C have equal value.)
12 HWK Assignment blem 12.10 ㎜ Review 1 Constants i Periodic Table PartA n ideal gas...
ch 10 4b
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