Question

A bus makes a trip according to the position-time graph shown in the liustration, what is the average acceleration in the graph? in km/h2 of the bus for the entire 3.5-h period sho n +39.d 005 1.0 1.5 2.0 2.5 3. 3,0 3.5

Answer 1

the velocity of the bus is " V "

V = final position - initial position / ( final time - initial time )

so in segment " A " the velocity is V_A = 30 - 0 / 1

= 30 km/h

in segment " C " the velocity is V_C = 36 - 42 / 3.5 - 2.2

= - 4.6153 km/h

so the average acceleration = final velocity - initial velocity / ( final time - initial time )

a = - 4.6153 - 30 / 3.5

a = - 9.890085 km/h²

a = - 9.9 or - 10 km/h²

so the average acceleration of the bus is a = - 9.9 or - 10 km/h²

or we can have so the average acceleration of the bus is a = - 0.00076312384 m/sec²