Consider the loop R1, R2, R6
given V1 = 20 and V2 = 60 , Vo = 90 supply
V1 + V2 + V6 = Vo =90
hence V6 = 10 V
V3 = V4 since R3 and R4 are parallel
V5 = 20 V given
V3 + V5 = V2 = 60 V
hence V3 = V4 = 60-20 = 40 V
Totel current entering (R3 + R4) = current leaving (R3+R4) = current through R5 = I5 = 6A
I4 = 2.0 A given
I4 +I3 = I5 = 6
I3 = 6-2 = 4.0A
R3/R4 = I4/I3 = 2/4 = 0.5
I6 = I2 +I5 ( sum of the current entering the node)
= 3.0 + 6.0 = 9.0 A
I1 = I2 + I3 + I6 ( total current entering the node is equal to that of leaving the node)
= 3.0 +4.0 +2.0 = 9.0 A
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