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The figure below shows a ball with mass m = 0.369 kg attached to the end of a thin rod with length L = 0.512 m and negligible

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Answer #1

A )

W_gravity = mg*2L = 0.369*9.8*2*.512= 3.7029888 J

B) mg 2L - mg*2L = 0 J  

C) mgL = 0.369*9.8*.512 =1.8514944 J

Work done = energy at that point

D) - 3.7029888 J

E) 0 J

F) -1.8514944 J   

G) same   

because potential energy independent of speed

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Goodluck for exam Comment in case any doubt, will reply for sure..

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