Question

16.26° 36.870 B A C 30 N FIGURE Q5.1 The 30 N weight shown in Figure Q5.1 is suspended from the ceiling by ropes
1. T 36.87 3687 16 26 1626 30 N T T 16.26 1626 3687 36.87 30N
HIGURE Q5.2 One of the correct free-body diagrams for this system is: Figure Q5.2 (a) Figure Q5.2 (b) Figure Q5.2 (c) Figure
2. TC Tc TC 36.87 1626 30 N 30 N 30 N 30 N (c) FIGURE Q5.3
A second correct free-body diagram for this system is: Figure Q5.3 (a) Figure Q5.3 (b) Figure Q5.3 (c) Figure Q5.3 (d)
3. One of the force equations is the following: (i) TB cos 16.26° - TA cos 36.87°Tc EF 0 (i) EF 0 TB cos 16.26° - TA cos 36.8
4. A second force equation is the following: (i) EFy 0 TA sin 36.87° - TB sin 16.26° + 30 N (ii) EFy 0 TA sin 36.87° + TB sin
5. The third equation is the following: ()EF 0 Tc 30 N EF 0 Tc +30 N (ii) (ii EF 0 TA Sin 36.87° TB Sin 16.26° 30 N (iv) EF 0
6. Calculate TA, the tension [in newtons] in rope A Enter answer... 7 Calculate TB, the tension [in newtons] in rope B Enter
16.26° 36.870 B A C 30 N FIGURE Q5.1 The 30 N weight shown in Figure Q5.1 is suspended from the ceiling by ropes
1. T 36.87 3687 16 26 1626 30 N T T 16.26 1626 3687 36.87 30N
HIGURE Q5.2 One of the correct free-body diagrams for this system is: Figure Q5.2 (a) Figure Q5.2 (b) Figure Q5.2 (c) Figure Q5.2 (d)
2. TC Tc TC 36.87 1626 30 N 30 N 30 N 30 N (c) FIGURE Q5.3
A second correct free-body diagram for this system is: Figure Q5.3 (a) Figure Q5.3 (b) Figure Q5.3 (c) Figure Q5.3 (d)
3. One of the force equations is the following: (i) TB cos 16.26° - TA cos 36.87°Tc EF 0 (i) EF 0 TB cos 16.26° - TA cos 36.87° (ii) EF 0 TB cos 16.26° +TA cos 36.87° Tc (iv) EF TB cos 16.26° TA cos 36.87° 0 Equation (i) Equation (ii) Equation (ii Equation (iv)
4. A second force equation is the following: (i) EFy 0 TA sin 36.87° - TB sin 16.26° + 30 N (ii) EFy 0 TA sin 36.87° + TB sin 16.26° - 30 N (i) EF 0 TA Sin 36.87° + TB sin 16.26° Tc (iv) ΣΕ TA sin 36.87° TB sin 16.26° 30 N 0 Equation (i) Equation (ii) Equation (iii) Equation (iv)
5. The third equation is the following: ()EF 0 Tc 30 N EF 0 Tc +30 N (ii) (ii EF 0 TA Sin 36.87° TB Sin 16.26° 30 N (iv) EF 0 TA sin 36.87° + Tg sin 16.26° - 30 N Figure (i) Figure (ii) Figure (ii) Figure (iv)
6. Calculate TA, the tension [in newtons] in rope A Enter answer... 7 Calculate TB, the tension [in newtons] in rope B Enter answer... 8 Calculate Tc, the tension [in newtons] in rope C Enter answer...
0 0
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Answer #1

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