Question

23. + -/0.1 points 0/4 Submissions Used Calculate the percent ionization of hypoiodous acid (HIO) in solutions of each of the following concentrations (Ka = 2.3e-11.) (a) 0.235 M % (b) 0.401 M % (C) 0.791 M %

Answer 1

Answer Let Initial concentration of HID is Co ICE table HEO + COM Initial Initial co Change + Equilibrium Eaw'liborum 6-* Gok * * kes fH7] (10-) [ko] 2.3 X 10-11 - . Since kais veny small n<<< . 2.3 X 10- = 2-3x10-1 = 2 ma 12.8 %10-W x co uc yio X Co pereent ionization = 23 Y1 -11 - - a -X100 - X100 2.3 Mo Xloo

CO= 0.235 m % ionization - 11 2.3 X 10 0.235 "X100 ) JJ.89x10-4 y. 0.40 M % ionization 2.3 X10-! X 100 ). 40 = 17:57 810-4 x.] 7.57 10-4 y. © Co = 0.791 'M % ionization - -1/2.3x10-11 1 X 100 0.791 = 5.39 X 10y 5:39 X10-9%.]