Question

25. + -/0.1 points 0/4 Submissions Used (a) Calculate the percent ionization of 0.00410 M propionic acid (Ka = 1.3e-05). % ionization = (b) Calculate the percent ionization of 0.00410 M propionic acid in a solution containing 0.0500 M sodium propionate. % ionization =

Answer 1

propionic acid : CH₂ Ch cooH (weak electroitte) (a) Ionization of weak electrocyte in pure water : нең сәon cң ең, соон e cң, ең соо" + Нt o -ca (c-ca) pure water red) I can Ka = cea for weak electrolyte indîl so, ka = ca2 > x= ka Given that; Ka 1.3*los and C= 0.00410 m so, a = = 0.056 V 0.00410 % lonization = s.6% [ 13x155 لا لا (6) Ionization of weak electrolyte in presence of common son: CH₂ Chcool Chcthcoon = CH₂ Ccoo & Ht 0.0500 C: -ca ta + Ca CHALCON c- Се oojootca CHCHC00Na] 0.0500m since, jonization is suppressed in the presence of common ion. s, СенсH, Coo 12 ордоо ч So, Graac 0.05ootca noosoo :. . - x)(oooº) 2.3 x 6 - oooo x4 >x=2.66104 7. lonization = 2.6x100 x 100 = 0.026%