Question

(a) Calculate the percent ionization of 0.00700 M propionic acid (Ka = 1.3e-05). % ionization = % (b) Calculate the percent ionization of 0.00700 M propionic acid in a solution containing 0.0570 M sodium propionate. % ionization = %

Answer 1

a) prosionic acid ionization is as follows Cu HS COOH MY + Cats Con Ka= [At] [ cansios 1 [latts cook] Akid dissociation constant of cals Cool ka = 1.34165 [+] = {3145600] =+ 1.34105 = *%0.00700 (1.3 x105) (0.00400) = 9-14168 X 0.000301M Percent ionization : [Salts cool] * X loo 0.00030) 0.00700X700 Perlent ionization: 4:37. 5) Chợ Cool = * * , scoop Kg 2 - 3 < 105 I 0.00700 o 0.0570 C - +* + x E 0.00700 -* * 0.0576 4X Kai + ][ 6.45:06] /[.69.Hçcoote] 1-341655 (00570+ y)/(0-00700 -x} C1-3X165) (0.00700-x): 0.0570 x + x 9.14168/3 465 30.0570% 7% *** 0057 of 3 - 7: y loºk ra . *20.00000159 Percent animation = 0.00000159 0.domoo - 0227"). ionization