Question

0.760 mol sample of methane gas at a temperature of 29.0 °C is found to occupy a volume of 25.8 liters. The pressure of this gas sample is mm Hg.

Answer 1

0 By the problem giren dată n=0.760 mol . Here, T 29.0°C - 302 K - na no. of mole 2 pressure V = Volume T = Temperature v = 25.8 liters Now, from equation of state PV = nRT тет . p= r comel x 0.0820 lit alim motta'x 302k R 25.8 lit p 3 p =0.729 alm = 0.729 almx 760 mmity I alm Tp = 554.4 mm Hg dată a By the problem giren p = 632 mm Hg a 632 mm Hg x = 0.831 alm 760 mm Hg

T = 298 K The mass of oxygen gas = 18.5 grams. so the mole of oxygen gas, n=. 18.5 grams = 1 grams/mol = 1.15 mol. from the Now equation of state pranRT nRT_ - V = lit als 0.082 1.15 mol x r = 1 x 0.082 lit alim mot klx 298K 0.831 am 33.816 liters. TV = L . = 33.816 The volume