please show all steps and write legibly so i can read. thanks. 6. [7] (Phys 144...
Hockey puck A is shot along the x-axis at 5.60 m/s at identical hockey puck B which is initially at rest on horizontal frictionless ice. The collision is off-center, and they scatter at the angles shown.a) [3] Find the speeds vA2 and vB2 of the pucks after the collision.b) [1] Find the percentage of kinetic energy converted into other forms during this collision.c) [3] Determine the coefficient of restitution for this collision. (Note: Since B is at rest initially, the...
Please be clear on which answer is which I got confused on a earlier question. thankss Two pucks collide on an air hockey table. Puck A has a mass of 30.0 g and is initially traveling in the +x direction at 7.40 m/s. Puck B has a mass of 120.0 g and is initially at rest. After the pucks collide, puck A moves away at an angle of 56.0 above the +x axis, while puck B travels at an angle...
Please help answer parts a, b, c, d. I tried all parts and think a and b might be right but c and d are wrong. Ignore my work. Thank you and I will rate well. 3. Atwo dimensional-elastic collision shows an elastic collision of two pucks on a frictionless air table. Puck A has mass 0.500 and puck B has mass ma 0.300 kg. Puck A has an initial velocity of 4.00 m/s in the positive x- direction and...
Here is the question. I cant get it right. please show steps A 0.30-kg puck, initially at rest on a frictionless horizontal surface, is struck by a 0.20-kg puck that is initially moving along the x-axis with a velocity of 4.3 m/s. After the collision, the 0.20-kg puck has a speed of 2.6 m/s at an angle of θ = 53° to the positive x-axis. (a) Determine the velocity of the 0.30-kg puck after the collision. magnitude direction (b) Find...
university of physics chap 8 example 8.12 question B angle alfa and Betta could you help me doing step by step to find the degree please? thank you (0.500 kg)(4.00 m/s) - (0.500 kg)(2.00 m/s)? 0.300 kg Vg2 = 4.47 m/s the details of the solution (Hint: Solve the first equation for and the second for sin B: square each equation and add. Si sin'B + cosB = 1, this eliminates B and leaves an equation you can solve for...