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JESTION 5 (20 Marks) The Managers for an insurance firm are interested in finding out if the number of new clients a broker b

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5.1)Scatter Diagram

64- 62- 60- 58 56 54- 52 50- 48 sales (R 000s) 46- 44 42 40- 38 36- 25 30 35 15 number of clients 10 5

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5.2) Pearson Correlation Coefficient (R) = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))

Let X = number of clients

Let Y = sales (R 000's)

X Values
∑ = 115
Mean = 19.167
∑(X - Mx)2 = SSx = 712.833

Y Values
∑ = 285
Mean = 47.5
∑(Y - My)2 = SSy = 633.5

X and Y Combined
N = 6
∑(X - Mx)(Y - My) = 653.5

Now Pearson Correlation Coefficient (R) can be calculated as below
R = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))

R = 653.5 / √((712.833)(633.5)) = 0.9725
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5.3) Linear Regression Equation

Here sum of our X's (Number of clients) = 115

Hense mean of X's (Mx) = 19.1667

Now sum of our Y's (sales) = 285

Hense mean of Y's (My)= 47.5

X-Mx Y-My (X-Mx)2 (X-Mx)(Y-My)
2.8333 4.5 8.0278 12.75
-13.1667 -10.5 173.3611 138.25
17.8333 16.5 318.0278 294.25
8.8333 7.5 78.0278 66.25
-9.1667 -6.5 84.0278 59.5833
-7.1667 -11.5 51.3611 82.4167
Sum 712.8333 653.5

Sum of squares (SSX) = 712.8333
Sum of products (SP) = 653.5

Regression Equation = Y = bX + a

b=SP/SSx = 653.5/712.83 = 0.91676

a=MY - bMX = 47.5 - (0.92*19.17) = 29.92869

Regression Equation = Y = bX + a = 0.91676X+29.92869

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